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Alex_Xolod [135]
3 years ago
12

Under appropriate conditions, nitrogen and hydrogen undergo a combination reaction to yield ammonia: N 2 (g) 3H 2 (g) 2NH3 (g) I

f the reaction yield is 87.5%, how many moles of N 2 are needed to produce 3.00 mol of NH 3
Chemistry
1 answer:
balandron [24]3 years ago
5 0

Answer:

We need 1.714 moles N2

Explanation:

Step 1: Data given

The reaction yield = 87.5 %

Number of moles NH3 produced = 3.00 moles

Step 2: The balanced equation

N2(g)+ 3H2(g) →2NH3(g)

Step 3: Calculate moles N2

For 2 moles NH3 produced we need 1 mol N2 and 3 moles H2

This means, if the yield was 100%, for 3.00 moles NH3 produced , we need 1.5 moles N2

For a 87.5 % yield:  

we need more N2, increased by a ratio of 100/87.5.

100/87.5 * 1.5 =  1.714 moles N2

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D. Same energy level but different sublevel.

<h3>Explanation</h3>

There are four quantum numbers [1]:

  • <em>n</em><em>, </em>the principal quantum number,
  • <em>l</em>, the orbital angular momentum quantum number,
  • <em>m_l</em>, the magnetic quantum number, and
  • <em>m_s</em>, the electron spin quantum number.

As their names might suggest:

  • <em>n </em>determines the main energy level of an electron.
  • <em>l</em> determines the type of sublevel of an electron.
  • Each sublevel might contain more than one orbital. <em>m_l</em> gives the orbital of an electron.
  • Each orbital contains up to two electrons. <em>m_s</em> tells two electrons in the same orbital apart.<em> </em>

The two electrons in question come from the same atom. The question suggests that they have the same <em>n</em>, <em>m_l</em>, and <em>m_s</em>. As a result, both electrons are in main energy level <em>n</em> = 3. They share the same spin.

However, the two electrons differ in their value of <em>l</em>.

  • <em>l </em>= 2 for the first electron. It belongs to a <em>d</em> sublevel.
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<h3>Reference</h3>

[1] Kamenko, Anastasiya, et. al, "Quantum Numbers", Physical & Theoretical Chemistry, Chemistry Libretexts, 24 Mar 2017.

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Answer:

The question is incomplete and confusing.

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  • In the net ionic equation, the spectator ions do not appear. They are: NO₃⁻ and K⁺. They would not be present in the net ionic equation, but they do in the complete ionic equation.

See below the details.

Explanation:

Which compound will not form ions?

<u />

<u>1. Write the balanced molecular equation:</u>

  • Pb(NO₃)₂(aq) + 2KI(aq) → PbI₂(s) + 2KNO₃(aq)

<u />

<u>2. Write the ionizations for the ionic aqueous compounds:</u>

<u />

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<u />

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Hence, since PbI₂(s) does not ionize, but stays in solid form, it will not form ions.

All, Pb⁺², NO₃⁻, K⁺, and I⁻ will be present in the total ionic equation.

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