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3 years ago

What's the mass in grams of 0.334 moles of sucrose (C12H22O11)?

Chemistry

1 answer:

Sonbull [250]3 years ago

3 0

Answer:

114.23g

Explanation:

Mass = xg

Mole = 0.334 mol

Molar mass of Sucrose

(C = 12, H = 1, O = 16)

C12H22O11

(12×12)+(1×22)+(16×11)

144 + 22 + 176

342g/mol

Mass = No of mole × Molar mass

Mass = 0.334 × 342

Mass = 114.228

Mass ≈ 114.23g

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1. Calculate the heat change associated with cooling a 350.0 g aluminum bar from

Amanda [17]

Answer:

14175 j heat released.

Explanation:

Given data:

Mass of aluminium = 350.0 g

Initial temperature = 70.0°C

Final temperature = 25.0°C

Specific heat capacity of Aluminium = 0.9 j/g.°C

Heat changed = ?

Solution:

Specific heat capacity:

It is the amount of heat required to raise the temperature of one gram of substance by one degree.

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

Heat change:

ΔT = Final temperature - initial temperature

ΔT = 25.0°C - 70°C

ΔT = -45°C

Q = m.c. ΔT

Q = 350 g × 0.9 j/g.°C × -45°C

Q = -14175 j

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2 years ago

Which types of reactions would result in a change in temperature?

Law Incorporation [45]

Answer:

Chemical reaction involves the breaking of bonds in the reactants and formation of bonds in the products. ... If a reaction is exothermic, more energy is released when the bonds of the products are formed than it takes to break the bonds of the reactants. This is the reason for temperature change during a reaction.

Explanation:

Here are just a few everyday demonstrations that temperature changes the rate of chemical reaction: Cookies bake faster at higher temperatures. Bread dough rises more quickly in a warm place than in a cool one.

6 0

3 years ago

What is the orbital hybridization of a central atom that has one lone pair and bonds to:

svlad2 [7]

$sp^3d$ is the type of orbital hybridization of a central atom that has one lone pair and bonds to four other atoms.

<h3>What is orbital hybridization?</h3>

In the context of valence bond theory, orbital hybridization (or hybridisation) refers to the idea of combining atomic orbitals to create new hybrid orbitals (with energies, forms, etc., distinct from the component atomic orbitals) suited for the pairing of electrons to form chemical bonds.

For instance, the valence-shell s orbital joins with three valence-shell p orbitals to generate four equivalent sp3 mixes that are arranged in a tetrahedral configuration around the carbon atom to connect to four distinct atoms.

Hybrid orbitals are symmetrically arranged in space and are helpful in the explanation of molecular geometry and atomic bonding characteristics. Usually, atomic orbitals with similar energies are combined to form hybrid orbitals.

Learn more about hybridization

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5 0

1 year ago

HELP PLEASE I HAVE A TEST TODAY AND I DON'T UNDERSTAND ANY OF THIS...

myrzilka [38]

Answer:

About 67 grams or 67.39 grams

Explanation:

First you would have to remember a few things:

enthalpy to melt ice is called enthalpy of fusion. this value is 6.02kJ/mol

of ice

it takes 4.18 joules to raise 1 gram of liquid water 1 degree C

water boils at 100 degrees C and water melts above 0 degrees C

1 kilojoules is 1000 joules

water's enthalpy of vaporization (steam) is 40.68 kJ/mol

a mole of water is 18.02 grams

we also have to assume the ice is at 0 degrees C

Step 1

Now start with your ice. The enthalpy of fusion for ice is calculated with this formula:

q = n x ΔH q= energy, n = moles of water, ΔH=enthalpy of fusion

Calculate how many moles of ice you have:

150g x (1 mol / 18.02 g) = 8.32 moles

Put that into the equation:

q = 8.32 mol x 6.02 = 50.09 kJ of energy to melt 150g of ice

Step 2

To raise 1 gram of water to the boiling point, it would take 4.18 joules times 100 (degrees C) or 418 joules.

So if it takes 418 joules for just 1 gram of water, it would take 150 times that amount to raise 150g to 100 degrees C. 418 x 150 = 62,700 joules or 62.7 kilojoules.

So far you have already used 50.09 kJ to melt the ice and another 62.7 kJ to bring the water to boiling. That's a total of 112.79 kJ.

Step 3

The final step is to see how much energy is left to vaporize the water.

Subtract the energy you used so far from what you were told you have.

265 kJ - 112.79 kJ = 152.21 kJ

Again q = mol x ΔH (vaporization)

You know you only have 152.21 kJ left so find out how many moles that will vaporize.

152.21 kJ = mol x 40.68 or mol = 152.21 / 40.68 = 3.74 moles

This tells you that you have vaporized 3.74 moles with the energy you have left.

Convert that back to grams.

3.74 mol x ( 18.02 g / 1 mol ) = 67.39 grams

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2 years ago

What is produced when a strong acid reacts with the bicarbonate buffer system in the human body?

Norma-Jean [14]

Carbonic acid is produced when a strong acid reacts with the bicarbonate buffer system in the human body.

7 0

3 years ago

Read 2 more answers