<u>Answer:</u> The volume of carbon dioxide gas at STP for given amount is 106.624 L
<u>Explanation:</u>
We are given:
Moles of carbon dioxide = 4.76 moles
<u>At STP:</u>
1 mole of a gas occupies a volume of 22.4 Liters
So, for 4.76 moles of carbon dioxide gas will occupy a volume of = 
Hence, the volume of carbon dioxide gas at STP for given amount is 106.624 L
Answer:
900 J/mol
Explanation:
Data provided:
Enthalpy of the pure liquid at 75° C = 100 J/mol
Enthalpy of the pure vapor at 75° C = 1000 J/mol
Now,
the heat of vaporization is the the change in enthalpy from the liquid state to the vapor stage.
Thus, mathematically,
The heat of vaporization at 75° C
= Enthalpy of the pure vapor at 75° C - Enthalpy of the pure liquid at 75° C
on substituting the values, we get
The heat of vaporization at 75° C = 1000 J/mol - 100 J/mol
or
The heat of vaporization at 75° C = 900 J/mol
Calcium carbon oxygen, calcium chlorine , carbon hydrogen oxygen, hydrogen chlorine, calcium oxygen hydrogen. pretty sure they’re right
Answer:
A chemical reaction is the change in chemical form rather than physical due to an outside force. This can come from something as simple as a change in temerature to as large as a specific element or compound.
Answer:
1.9 L
Explanation:
Step 1: Given data
- Initial pressure (P₁): 1.5 atm
- Initial volume (V₁): 3.0 L
- Initial temperature (T₁): 293 K
- Final pressure (P₂): 2.5 atm
- Final temperature (T₂): 303 K
Step 2: Calculate the final volume of the gas
If we assume ideal behavior, we can calculate the final volume of the gas using the combined gas law.
P₁ × V₁ / T₁ = P₂ × V₂ / T₂
V₂ = P₁ × V₁ × T₂ / T₁ × P₂
V₂ = 1.5 atm × 3.0 L × 303 K / 293 K × 2.5 atm = 1.9 L
