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Vadim26 [7]
3 years ago
10

How many grams are in 2.30 x 10^24 atoms in silver

Chemistry
1 answer:
PtichkaEL [24]3 years ago
4 0

411.984 grams

The atomic mass of Silver is 107.8682 by the periodic chart I have here. That means that 1 mole of Silver masses

107.8682 grams if the Silver is pure.

I mole of any element like silver is also 6.022 X 10^23 atoms of silver.

10^24 atoms is therefore more than a mole. You specified

2.3 x 10^24 atoms, so the number of moles will be

(2.3 X 10^24)divided by 6.022 X 10^23 = 3.819 moles

this number X 107.8682 grams/mole gives us 411.984 grams

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The freezing point of benzene C6H6 is 5.50°C at 1 atmosphere. A nonvolatile, nonelectrolyte that dissolves in benzene is DDT . H
Vlad1618 [11]

Answer: 0.028 grams

Explanation:

Depression in freezing point :

Formula used for lowering in freezing point is,

\Delta T_f=k_f\times m

or,

\Delta T_f=k_f\times \frac{\text{ Mass of solute in g}\times 1000}{\text {Molar mass of solute}\times \text{ Mass of solvent in g}}

where,

\Delta T_f = change in freezing point

k_f = freezing point constant  (for benzene} =5.12^0Ckg/mol

m = molality

Putting in the values we get:

0.400^0C=5.12\times \frac{\text{ Mass of solute in g}\times 1000}{354.5\times 209.0}

{\text{ Mass of solute in g}}=0.028g

0.028 grams of DDT (solute) must be dissolved in 209.0 grams of benzene to reduce the freezing point by 0.400°C.

4 0
3 years ago
If 2.0 mol of Zn is mixed with 3.0 mol<br> of HCl, which reactant will be limiting?
Soloha48 [4]

The following Balanced Reaction will take place:

Zn + 2HCl → ZnCl₂ + H₂

In the question, we have 2 moles of Zinc and 3 moles of HCl for this reaction

<u>Amount of HCl required to completely react with 2 moles of Zn:</u>

Since we need 2 moles of HCl for every mole of Zn, we will need 2(2) = 4 moles of HCl for every 2 moles of Zn

<u>Identifying the Limiting Reagent:</u>

But we are only given 3 moles of HCl where we need 4 moles to completely react.

So, since HCl is in less amount, it is the Limiting Reagent

8 0
3 years ago
Unscramble the word nlpituloo
nadezda [96]
Hello

The word is "pollution"

Hope this helps and have a great day!
3 0
3 years ago
Read 2 more answers
1. During an endothermic chemical reaction, a gas is consumed and a liquid produced.
tino4ka555 [31]
1. No
2.No
I hope this helps:)
8 0
3 years ago
How many moles is 22.4 liters of oxygen gas at standard temperature and pressure represent
makkiz [27]

Answer:

So 1 mole

Explanation:

PV = nRT

P = Pressure atm

V = Volume L

n = Moles

R = 0.08206 L·atm·mol−1·K−1.

T = Temperature K

standard temperature = 273K

standard pressure = 1 atm

22.4 liters of oxygen

Ok so we have

V = 22.4

P = 1 atm

PV = nRT

n = PV/RT

n = 22.4/(0.08206 x 273)

n  = 22.4/22.40

n = 1 mole

7 0
3 years ago
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