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3 years ago

How many grams are in 2.30 x 10^24 atoms in silver

Chemistry

1 answer:

PtichkaEL [24]3 years ago

4 0

411.984 grams

The atomic mass of Silver is 107.8682 by the periodic chart I have here. That means that 1 mole of Silver masses

107.8682 grams if the Silver is pure.

I mole of any element like silver is also 6.022 X 10^23 atoms of silver.

10^24 atoms is therefore more than a mole. You specified

2.3 x 10^24 atoms, so the number of moles will be

(2.3 X 10^24)divided by 6.022 X 10^23 = 3.819 moles

this number X 107.8682 grams/mole gives us 411.984 grams

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2 years ago

The reactant concentration in a second-order reaction was 0.560 m after 115 s and 3.30×10−2 m after 735 s . what is the rate con

Aloiza [94]

Use the formula for second order reaction:

$\frac{1}{C} = \frac{1}{C_0} + kt$

C = concentration at time t
C0 = initial conc.
k = rate constant
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1st equation : $\frac{1}{0.56} = \frac{1}{C_0} + 115k$

2nd Equation: $\frac{1}{0.033} = \frac{1}{C_0} + 735k$

Find $\frac{1}{C_0}$ from 1st equation and put it in 2nd equation:

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3 years ago

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Explanation:

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2 years ago

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3 years ago

What is the coefficient for H2O when the equation ? Ca(OH)2(aq) + ? H3PO4(aq) → ? Ca3(PO4)2(s) + ? H2O(ℓ) is balanced using the

kari74 [83]

Answer:

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Explanation:

Unbalanced equation: $Ca(OH)_{2}(aq.)+H_{3}PO_{4}(aq.)\rightarrow Ca_{3}(PO_{4})_{2}(s)+H_{2}O(l)$

Balance Ca: $3Ca(OH)_{2}(aq.)+H_{3}PO_{4}(aq.)\rightarrow Ca_{3}(PO_{4})_{2}(s)+H_{2}O(l)$

Balance $PO_{4}$ : $3Ca(OH)_{2}(aq.)+2H_{3}PO_{4}(aq.)\rightarrow Ca_{3}(PO_{4})_{2}(s)+H_{2}O(l)$

Balance H and O: $3Ca(OH)_{2}(aq.)+2H_{3}PO_{4}(aq.)\rightarrow Ca_{3}(PO_{4})_{2}(s)+6H_{2}O(l)$

Balanced equation: $3Ca(OH)_{2}(aq.)+2H_{3}PO_{4}(aq.)\rightarrow Ca_{3}(PO_{4})_{2}(s)+6H_{2}O(l)$

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3 years ago