the percent yield of the reaction is 100%.
The percent yield is calculated as the experimental yield divided by the theoretical yield x 100%:
% yield = actual yield / theoretical yield * 100%
% yield of a reaction in this case Rate
In this case, the molar mass of NaBr is 102.9 g / mol, as you know:
444 actual yield = 7.08 mol x 102.9 g / mol = 728.532 g
theoretical yield = 7.08 mol x 102.9 g / mol = 728.532 g
, Replaced by the definition of percent yield:
percent yield = 728.532 grams / 728.532 grams * 100%
percent yield = 100%
Finally, the percent yield of the reaction is 100%.
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FeBr3 is iron bromide. Also known as iron bromide. Iron bromide is an ionic compound in which iron is in a +3 oxidation state.
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If you add them up: 2+2+6 = 10, you will know it's Neon, which is written as Ne
<em>I</em><em> </em><em>DONT</em><em> </em><em>KNOW</em><em> </em><em>THE</em><em> </em><em>ANSWER</em><em> </em><em>OF</em><em> </em><em>NO</em><em>.</em><em>B</em>
<em>SO</em><em> </em><em>SORRY</em><em> </em><em>FOR</em><em> </em><em>THAT</em><em>!</em><em>!</em><em>!</em>
C magnetic repulsion, forgive me if I’m wrong