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elixir [45]
3 years ago
9

I NEED THIS ANSWER NOW

Mathematics
2 answers:
storchak [24]3 years ago
7 0

Answer: B

Step-by-step explanation:wouldnt it be B because it is counting the sides from one dot to the other

SOVA2 [1]3 years ago
4 0
b its hope that helps
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Feliz [49]

Answer:

11.85 ounces to 12.35 ounces

Step-by-step explanation:

A P E X

7 0
2 years ago
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(6, -5) reflected aross the y axis
m_a_m_a [10]

Answer:

Then the new point is (-6,-5)

Step-by-step explanation:

8 0
2 years ago
(w-2) (w+5) <br> I need help I don't understand ...
Phantasy [73]
<h3>Answer: w^2 + 3w - 10</h3>

===============================================

Work Shown:

Let x = w-2

This will allow us to replace the (w-2) with x to get...

(w-2)(w+5)

x(w+5)

x*w + x*5 ... distribute

w(x) + 5(x)

Now replace x with w-2 and distribute again

w(x) + 5(x)

w(w-2) + 5(w-2)

w*w + w*(-2) + 5*w + 5*(-2)

w^2 - 2w + 5w - 10

w^2 + 3w - 10

6 0
3 years ago
Read 2 more answers
What is the distance from the origin to point P graphed on the complex plane below
anastassius [24]

Answer:

b) √29

Step-by-step explanation:

Given: The origin is (0, 0), the point P is (2, -5).

We need to use the distance formula.

Distance formula =

Here x2 = 2, x 1 = 0, y1 =0, y2 = -5

Distance =

= √(4 + 25)

= √29

The answer is b) √29

Hope you will understand the concepts

Thank you!!

8 0
3 years ago
Assume that the national credit card interest rate is 12.83 percent. A study of 62 college students finds that their average int
meriva

Answer:

b)  95 percent confidence interval for this single-sample t test

[11.64, 16.36]

Step-by-step explanation:

Explanation:-

Given data  a study of 62 college students finds that their average interest rate is 14 percent with a standard deviation of 9.3 percent.

Sample size 'n' =62

sample mean x⁻ = 14  

sample standard deviation 'S' = 9.3

<u>95 percent confidence interval for this single-sample t test</u>

The values are (x^{-} - t_{0.05} \frac{S}{\sqrt{n} } ,x^{-}+t_{0.05}\frac{S}{\sqrt{n} })  the <u>95 percent confidence interval for the population mean  'μ'</u>

Degrees of freedom γ=n-1=62-1=61

t₀.₀₅ = 1.9996 at 61 degrees of freedom

(14 - 1.9996\frac{9.3}{\sqrt{62} } ,14+1.9996\frac{9.3}{\sqrt{62} })

(14-2.361 , 14 + 2.361)

[(11.64 , 16.36]

<u>Conclusion:-</u>

95 percent confidence interval for this single-sample t test

[11.64, 16.36]

<u></u>

6 0
3 years ago
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