Since we are already given the amount of jumps from the first trial, and how much it should be increased by on each succeeding trial, we can already solve for the amount of jumps from the first through tenth trials. Starting from 5 and adding 3 each time, we get: 5 8 (11) 14 17 20 23 26 29 32, with 11 being the third trial.
Having been provided 2 different sigma notations, which I assume are choices to the question, we can substitute the initial value to see if it does match the result of the 3rd trial which we obtained by manual adding.
Let us try it below:
Sigma notation 1:
10
<span> Σ (2i + 3)
</span>i = 3
@ i = 3
2(3) + 3
12
The first sigma notation does not have the same result, so we move on to the next.
10
<span> Σ (3i + 2)
</span><span>i = 3
</span>
When i = 3; <span>3(3) + 2 = 11. (OK)
</span>
Since the 3rd trial is a match, we test it with the other values for the 4th through 10th trials.
When i = 4; <span>3(4) + 2 = 14. (OK)
</span>When i = 5; <span>3(5) + 2 = 17. (OK)
</span>When i = 6; <span>3(6) + 2 = 20. (OK)
</span>When i = 7; 3(7) + 2 = 23. (OK)
When i = 8; <span>3(8) + 2 = 26. (OK)
</span>When i = 9; <span>3(9) + 2 = 29. (OK)
</span>When i = 10; <span>3(10) + 2 = 32. (OK)
Adding the results from her 3rd through 10th trials: </span><span>11 + 14 + 17 + 20 + 23 + 26 + 29 + 32 = 172.
</span>
Therefore, the total jumps she had made from her third to tenth trips is 172.
3+6x+3x+ 6 = 180
9x + 9 = 180
9x = 171
x = 19
Answer:
7cm
14cm
dπ or 2r π
14π or 2(7π)
Step-by-step explanation:
Radius = 7cm
Diameter = 7 x 2 = 14cm
Circumference = 2 x π x r = dπ
Circumference Value = 2 x π x 7 = 14π
Answer:
lets use what we know.
given lengths are: 6, 3, 6, and 15.
We need to split the right triangle from the small little rectangle.
Now we add the lengths of the triangle to get the full length:
6 + 6 = 12
now we need to find the base:
15 - 3 = 12
Now we get our area of the triangle:
12 x 12 = 144
144 divided by 2 = 72
Now the small rectangle's area:
6 x 3 = 18
Add both of their areas to get:
72 + 18 = 90 ft2
