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2 years ago

A circle has radius of 5cm

Mathematics

2 answers:

victus00 [196]2 years ago

8 0

Answer:

A) 31.4

B)78.5

Step-by-step explanation:

A)2(pi)(r)

2*3.14*5=31.4

B)(pi)(r^2)

3.14*5^2=78.5

natita [175]2 years ago

5 0

31,4
75,8
Is the right answer

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2. Determine if either of the following equations are functions? Draw the graphs and explain how

nekit [7.7K]

Answer:

Both equation represent functions

Step-by-step explanation:

The function is the relation that for each input, there is only one output.

A. Consider the equation

$y=-\dfrac{3}{5}x+2$

This equation represents the function, because for each input value x, there is exactly one output value y.

To check whether the equation represents a function, you can use vertical line test. If all vertical lines intersect the graph of the function in one point, then the equation represents the function.

When you intersect the graph of the function $y=-\dfrac{3}{5}x+2$ with vertical lines, there will be only one point of intersection (see blue graph in attached diagram). So this equation represents the function.

B. Consider the equation

$y=x-x^2$

This equation represents the function, because for each input value x, there is exactly one output value y.

When you intersect the graph of the function $y=x-x^2$ with vertical lines, there will be only one point of intersection (see green graph in attached diagram). So this equation represents the function.

4 0

2 years ago

Please Help Quick ASAP Hurry This is Pre-Algebra 1

Svet_ta [14]

Answer:

d=1.4

Step-by-step explanation:

cuz 10-1.4=8.6

6 0

2 years ago

Read 2 more answers

-3.5.-12=42 O True O False

Xelga [282]

It’s false because if you take a negative number away from another negative number it would give you another negative number not a positive number!

5 0

2 years ago

HELP! Find the value of sin 0 if tan 0 = 4; 180 < 0< 270

BabaBlast [244]

Hi there! Use the following identities below to help with your problem.

$\large \boxed{sin \theta = tan \theta cos \theta} \\ \large \boxed{tan^{2} \theta + 1 = {sec}^{2} \theta}$

What we know is our tangent value. We are going to use the tan²θ+1 = sec²θ to find the value of cosθ. Substitute tanθ = 4 in the second identity.

$\large{ {4}^{2} + 1 = {sec}^{2} \theta } \\ \large{16 + 1 = {sec}^{2} \theta } \\ \large{ {sec}^{2} \theta = 17}$

As we know, sec²θ = 1/cos²θ.

$\large \boxed{sec \theta = \frac{1}{cos \theta} } \\ \large \boxed{ {sec}^{2} \theta = \frac{1}{ {cos}^{2} \theta} }$

And thus,

$\large{ {cos}^{2} \theta = \frac{1}{17}} \\ \large{cos \theta = \frac{ \sqrt{1} }{ \sqrt{17} } } \\ \large{cos \theta = \frac{1}{ \sqrt{17} } \longrightarrow \frac{ \sqrt{17} }{17} }$