Answer:
2600 kg has 4 significant figures
Explanation:
Any different number to zero is a significant figure
For example, 1.8 → 2 significant figures
When you have 0 in the middle of two numbers, we consider it as a significant number
For example, 3.02 → 3 significant figures
When you have 0 on the left in the measure, we do not consider as a sgnificant figures
For example 0.0010 → 2 significant figures (10)
3.0 → 2 significant figures (0 is on the right, not the left)
C. Of the products is equal to the reactants.
Good luck out there! :)
I think that the answer is (D)... I hope this helped
Amount of Niobium-91 initially
= 300/91 =3.2967mol
2040 years = 3 ×680 = 3 half-lives
therefore, amount left = 0.4121mol
mass of Niobium-91 remaining = 0.4121 ×91 =37.5g
Answer:
8.61 mL of the HCl solution
Explanation:
The reaction that takes place is:
- 2HCl + Mg(OH)₂ → MgCl₂ + 2H₂O
From the given mass of Mg(OH)₂, we can calculate <u>the moles of HCl that are neutralized</u>:
- 4x10² mg = 400 mg = 0.400g
- 0.400g Mg(OH)₂ ÷ 58.32g/1mol = 6.859*10⁻³ mol Mg(OH)₂
- 6.859*10⁻³ mol Mg(OH)₂ *
3.429x10⁻³ mol HCl
Finally, to calculate the volume of an HCl solution, we need both the moles and the concentration. We can <u>calculate the concentration using the pH value</u>:
= [H⁺]
- 0.0398 M = [H⁺] = [HCl] *Because HCl is a strong acid*
Thus, the volume is:
- 0.0398 M = 3.429x10⁻³mol HCl / Volume
- Volume = 8.616x10⁻³ L = 8.62 mL