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3 years ago

How many liters of fluorine gas, at standard temperature and pressure, will react with 23.5 grams of potassium metal?

1 answer:

8 0

The balanced chemical reaction is written as:

<span>2K + F2 ---> 2 KF

We are given the amount of potassium metal to be used in the reaction. This will be the starting point for the calculation. We do as follows:

23.5 g K ( 1 mol / 39.1 g ) ( 1 mol F2/2 mol K ) ( 22.4 L / 1 mol ) = 13.46 L F2

</span>

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Answer:

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Solution: The force of attraction is calculated by using equation,

$F = \dfrac{k \times q_1 q_2}{ \r^2}$ ---(1)

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