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MAXImum [283]
2 years ago
6

Help :D .......................

Mathematics
1 answer:
LUCKY_DIMON [66]2 years ago
7 0

Answer:

The circunference is represented by the equation is x^{2}+y^{2}-6\cdot x +4\cdot y +9=0.

The graph of this function is presented in the attachment.

Step-by-step explanation:

The general equation of the circunferece is defined by the following formula:

x^{2}+y^{2}+A\cdot x + B\cdot y + C = 0 (1)

We can determine the value of the coefficients by knowing three distinct points: (x_{1}, y_{1}) = (3,0), (x_{2},y_{2}) = (5,-2), (x_{3},y_{3}) = (1, -2)

The system of linear equations is:

3\cdot A + C = -9 (2)

5\cdot A -2\cdot B + C = -29 (3)

A -2\cdot B + C = -5 (4)

The solution of this system is: A = -6, B = 4, C = 9.

The circunference is represented by the equation is x^{2}+y^{2}-6\cdot x +4\cdot y +9=0.

The graph of this function is presented in the attachment.

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Lelu [443]
Hello! To find the answer to this, we must add all of the first 5 numbers. When you do that, the sum should be 81. You must do 16 * 6 to find the number of points combined he needs to add up to the average. 16 * 6 = 96. 96 - 81 = 15. On the 6th test, you must score 15 points to have an average of 16 points. The answer is 15.
8 0
3 years ago
I need alot of help figuring out this problemm TRIG HW​
leva [86]

Answer:

x = 15

y = 15√3

Step-by-step explanation:

This is a special right triangle with angle measures 30° 60° 90°

The side lengths should be x 2x x√3

If the measure of hypotenuse 30 then the side length that sees 30° should be half of it so x = 15 and y = 15√3

6 0
3 years ago
Evaluate C_n.xP^xQn-x For the given n=7, x=2, p=1/2
r-ruslan [8.4K]

Answer:

The value of given expression is \frac{21}{128}.

Step-by-step explanation:

Given information: n=7, x=2, p=1/2

q=1-p=1-\frac{1}{2}=\frac{1}{2}

The given expression is

C(n,x)p^xq^{n-x}

It can be written as

^nC_xp^xq^{n-x}

Substitute n=7, x=2, p=1/2 and q=1/2 in the above formula.

^7C_2(\frac{1}{2})^2(\frac{1}{2})^{7-2}

\frac{7!}{2!(7-2)!}(\frac{1}{2})^2(\frac{1}{2})^{5}

\frac{7!}{2!5!}(\frac{1}{2})^{2+5}

\frac{7\times 6\times 5!}{2\times 5!}(\frac{1}{2})^{2+5}

21(\frac{1}{2})^{7}

\frac{21}{128}

Therefore the value of given expression is \frac{21}{128}.

7 0
3 years ago
Solve the system of equations using multiplication. 3x – 3y = –3 5x – y = –13 What is the solution of the system?
love history [14]

ANSWER

The solution is

x=-3,y=-2

EXPLANATION

First equation

3x – 3y = –3

Second Equation:

5x – y = –13

Multiply the second equation by 3 to get:

Third equation:

15x-3y=-39

Subtract the first equation from the third equation:

15x - 3x =  - 39 -  - 3

12x =  - 36

Divide both sides by 12,

x =  \frac{ - 36}{12}  =  - 3

Put x=-3 into the first equation:

3( - 3) - 3y =  - 3

- 9  - 3y =  - 3

Group like terms,

- 3y =  - 3 + 9

- 3y = 6

y =  - 2

The solution is

x=-3,y=-2

6 0
3 years ago
What is value of the X? And what is the value of the missing angle? Pls help
sasho [114]
So it work like this
180-72= 108
x+4=108
x=108-4
x=104
7 0
3 years ago
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