I believe it would be the reptile kingdom!
Answer:
d. Monosomy X is the only viable monosomy known to occur in humans.
Explanation:
Human have 22 pair of homologous chromosomoses and an extra pair of sex chromosomes. While in males the sex chromosomes are X and Y , females have two chromosomes X . Anyway, in normal conditions the total number of chromosomomes that humans have in their cells is 46 (23 pair of chromosomes).
Aneuploidy is a biological condition where an individual have an abnormal number of chromosomes in their cells. In humans for examples, this would be a human having more or less than 46 chromosomes.
The Turner syndrome also called monosomy X is an aneuploidy where one of the X chromosomes is missing in a female. Although under constant supervision, people with Turner syndrome have viable healthy lives. However this is the only monosomy that occur in humans that is compatible with life.
Answer:
E) Either anaphase I or II
Explanation:
Failure of segregation of homologous chromosomes during anaphase I or failure of segregation of sister chromatids during anaphase II leads to the presence of the abnormal number of chromosomes in resultant gametes. In the given example, the egg mother cell with 48 chromosomes (24 pairs) would enter meiosis I but the failure of one pair of homologous chromosomes to segregate from each other followed by normal meiosis II would result in the formation of two gametes with one extra chromosome and two gametes with one less chromosome.
On the other hand, if the nondisjunction occurs at anaphase II of meiosis II, two normal gametes, one gamete with one extra chromosome and one gamete with one less chromosome will be formed. Therefore, nondisjunction at anaphase I or anaphase II would have resulted in the production of eggs with one extra chromosome.
