Let the distance of Judy from intersection is x and distance of Jackie from intersection is y.
We convert the given information to equations, step by step.
Point 1: When Jackie is 1 mile farther from the intersection than Judy.
This means y is 1 mile more than x.
So,
y = 1 + x
Point 2: The distance between them is 2 miles more than Judy’s distance from the intersection.
Distance between is x+ y.
So, x+y is 2 miles more than y.
x+y = y + 2
⇒
x = 2
From point 1 we have:
y = 1 + x = 1+ 2 = 3
So,
Distance of Judy from intersection is 2 miles and distance of Jackie from intersection is 3 miles.
(-4,-24) (-1,-9) (1,1) (2,6) (4,16)
Answer:
$ 8,695.35
Step-by-step explanation:
This is a compound interest question
Amount after t years = A = P(1 + r/n)^nt
Where P = Initial Amount saved
r = interest rate
t = time in years
n = compounding frequency
A = 10,000
r = 3.5 %
t = 21 - 17 = 4 years
n = Compounded monthly = 12
Step 1
Converting R percent to r a decimal
r = R/100 = 3.5%/100 = 0.035 per year.
P = A / (1 + r/n)^nt
Solving our equation:
P = 10000 / ( 1 + (0.035/12)^12 ×4 =
P = $8,695.35
The principal investment required to get a total amount, principal plus interest, of $10,000.00 from interest compounded monthly at a rate of 3.5% per year for 4 years is $8,695.35.
