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3 years ago

How does charging by conduction compare with charging by induction?

Physics

2 answers:

Nadusha1986 [10]3 years ago

7 0

Answer:

Oppositely charged objects form in induction but not in conduction.

Explanation:

in induction phenomenon the charged object is placed near a neutral conductor. then due to electric field of the charged object the neutral conductor will have charge separation in it. Here opposite charge come near the surface which is known as induction

While in conduction phenomenon the neutral object is made contact with the charged body due to which the charge is transferred to the neutral object

here the same charge will occur in the neutral object as that of charge body is having on it

so here correct answer will be

Oppositely charged objects form in induction but not in conduction.

daser333 [38]3 years ago

5 0

Oppositely charged objects form in induction but not in conduction.

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A dog in an open field runs 11.0 m east and then 28.0 m in a direction 49.0 ∘ west of north. In what direction must the dog then

Ede4ka [16]

Answer:

$\theta=19.03 SE$

Explanation:

From the question we are told that:

$d_1=11.0m East$

$d_2=28.0m 49 \textdegree west\ north$

$d_3=10m south$

Generally the equation for Resolutions is mathematically given by

$d_x=-11-(-28sin49)$

$d_x=10.132m$

Where

$d_y=-11-(28cos49)$

$d_y=-29.37m$

Generally the equation for Direction is mathematically given by

$\theta=tan^{-1}(\frac{dx}{dy})$

$\theta=tan^{-1}(\frac{10.132}{29.37})$

$\theta=19.03 SE$

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3 years ago

How long does a 50 kW pump motor have to run to pump 500 cubic meters of water from a 180m deep mine

Ghella [55]

Answer:

t = 17658 s = 294.3 min = 4.9 h

Explanation:

The general formula for power is:

$P = \frac{W}{t}$

where,

P = Power of the Motor = 50 KW = 50000 W

W = Work Done by Motor = Change in P.E of Water = mgh

g = acceleration due to gravity = 9.81 m/s²

m = mass of water = ρV

h = depth of water = 180 m

ρ = density of water = 1000 kg/m³

V = Volume of Water = 500 m³

t = time taken = ?

Therefore,

$P = \frac{mgh}{t}=\frac{\rho Vgh}{t}\\\\t = \frac{\rho Vgh}{P}\\\\t = \frac{(1000\ kg/m^3)(500\ m^3)(9.81\ m/s^2)(180\ m)}{50000\ W}\\\\$

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3 years ago

n alpha particle (q = +2e, m = 4.00 u) travels in a circular path of radius 5.94 cm in a uniform magnetic field with B = 1.10 T.

9966 [12]

Answer:

a). V = 3.13*10⁶ m/s

b). T = 1.19*10^-7s

c). K.E = 2.04*10⁵

d). V = 1.02*10⁵V

Explanation:

q = +2e

M = 4.0u

r = 5.94cm = 0.0594m

B = 1.10T

1u = 1.67 * 10^-27kg

M = 4.0 * 1.67*10^-27 = 6.68*10^-27kg

a). Centripetal force = magnetic force

Mv / r = qB

V = qBr / m

V = [(2 * 1.60*10^-19) * 1.10 * 0.0594] / 6.68*10^-27

V = 2.09088 * 10^-20 / 6.68 * 10^-27

V = 3.13*10⁶ m/s

b). Period of revolution.

T = 2Πr / v

T = (2*π*0.0594) / 3.13*10⁶

T = 1.19*10⁻⁷s

c). kinetic energy = ½mv²

K.E = ½ * 6.68*10^-27 * (3.13*10⁶)²

K.E = 3.27*10^-14J

1ev = 1.60*10^-19J

xeV = 3.27*10^-14J

X = 2.04*10⁵eV

K.E = 2.04*10⁵eV

d). K.E = qV

V = K / q

V = 2.04*10⁵ / (2eV).....2e-

V = 1.02*10⁵V

7 0

3 years ago

In an experiment, a rectangular block with height h is allowed to float in two separate liquids. In the first liquid, which is w

Amiraneli [1.4K]

Answer:

The relative density of the second liquid is 7.

Explanation:

From archimede's principle we know that the force that a liquid exerts on a object equals to the weight of the liquid that the object displaces.

Let us assume that the volume of the object is 'V'

Thus for the liquid in which the block is completely submerged

The buoyant force should be equal to weight of liquid

Mathematically

$F_{buoyant}=Weight\\\\\rho _{1}\times V\times g=m\times g\\\\\therefore \rho _{1}=\frac{m}{V}...............(i)$

Thus for the liquid in which the block is 1/7 submerged

The buoyant force should be equal to weight of liquid

Mathematically

$F'_{buoyant}=Weight\\\\\rho _{2}\times \frac{V}{7}\times g=m\times g\\\\\therefore \rho _{2}=\frac{7m}{V}.................(ii)$

Comparing equation 'i' and 'ii' we see that

$\rho_{2}=7\times \rho _{1}$

Since the first liquid is water thus $\rho _{1}=1gm/cm^3$

Thus the relative density of the second liquid is 7.

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3 years ago

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BigorU [14]

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2 years ago