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ivanzaharov [21]
3 years ago
14

A 50-kg box is placed in the bed of a truck. the coefficient of static friction between the box and the truck bed is 0.54. if th

e truck is traveling at 100 km/h then calculate the minimum distance the truck can stop in without the box sliding into the cab.
Physics
1 answer:
miss Akunina [59]3 years ago
4 0
3 is the answer i think so
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A friend climbs an apple tree and drops a 0.22-kg apple from rest to you, standing 3.5 m below. When you catch the apple, you br
ella [17]

Answer: (A) velocity = 2.8m/s

(B) Average force = 1.9536 Newtons

Explanation:

Find detailed explanation in the attached picture

3 0
3 years ago
How is the potential difference same in capacitors arranged in parallel combination?​
zimovet [89]

Answer:

<h2>Potential difference across capacitors in parallel </h2>

Two or more capacitors are said to be connected in parallel if each one of them is connected across the same two points. In a parallel combination of capacitors potential difference across each capacitor is same but each capacitor will store different charge.

8 0
3 years ago
A potential energy function for a system in which a two-dimensional force acts is of the form U = 3x6y − 5x. Find the force that
liq [111]

Answer:

Force, F=((-18x^5y+5)i+(-3x^6)j)\ N

Explanation:

Given that,

A potential energy function for a system in which a two-dimensional force acts is of the form of :

U=3x^6y-5x

We need to find the force that acts at the point (x, y). The force in 2 dimensional with components is given by :

F=(\dfrac{-dU}{dx},\dfrac{-dU}{dy})\\\\F=(\dfrac{-d(3x^6y-5x)}{dx},\dfrac{d(3x^6y-5x)}{dy})\\\\F=(-(18x^5y-5)),(-(3x^6))\\\\F=((-18x^5y+5)i+(-3x^6)j)\ N

So, the force acting at the point (x,y) is ((-18x^5y+5)i+(-3x^6)j)\ N. Hence, this is the required solution.

7 0
3 years ago
How does the mass and size of a dwarf star compare with mass and size of the sun
Murljashka [212]
Das is from my star nerd bro schwarzschildradius

our sun is actually a dwarf star
some dwarf stars are larger than our sun
some dwarf stars are smaller than our sun

so there is actually no differnce between the sun an a dwarf star
5 0
3 years ago
Someone help me haha;(
Nikitich [7]

Answer: vf = 51 m/s

d = 112 m

Explanation: Solution attached:

To find vf we use acceleration equation:

a = vf - vi / t

Derive to find vf

vf = at + vi

Substitute the values

vf = 3.5 m/s² ( 8.0 s) + 23 m/s

= 51 m/s

To solve for distance we use

d = (∆v)² / 2a

= (51 m/s - 23 m/s )² / 2 ( 3.5 m/s²)

= (28 m/s)² / 7 m/s²

= 784 m/s / 7 m/s²

= 112 m

6 0
3 years ago
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