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2 years ago

Which of these channel members is last in the distribution channel?

Business

2 answers:

timofeeve [1]2 years ago

8 0

Answer:

Explanation:

They are the ones to use to products.

mote1985 [20]2 years ago

4 0

Answer:

C. Consumer

Explanation:

Took the test

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Heather is sixteen but looks much older. she goes into a jewelry store and buys a diamond bracelet with the money she has been s

brilliants [131]

D is the right answer I suppose

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3 years ago

Of money's three functions, the one that distinguishes money from other assets is:

NNADVOKAT [17]

Answer:

Medium of Exchange

Explanation:

The main function that distinguishes money from other assets is that everybody accept the money as a medium of exchange, either for our job or to buy things that we are interested.

Always through history the main function of money was to be a medium of exchange because at the begining money didn't exist so you needed to use different things, first salt, then precious metal and today money as we know.

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3 years ago

A company's unadjusted trial balance shows a debit balance in the allowance for doubtful accounts. This means that a. The compan

ELEN [110]

Answer:

d. Both a and b above are correct.

Explanation:

In the case when the company unadjusted trial balance reflect a debit balance of allowance for doubtful debts so this represent that the company would have more written off account receivable that would be shown in the beginning balance of the allowance. Also the company should record the bad debt expense as more as the debit balance of the non-adjusted allowance

Hence, the last option is correct

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2 years ago

A body in the solar system has a period of 10,759.22 days and a perihelion speed of 10.18 km/s. a. Calculate the aphelion radius

anastassius [24]

Answer:

Explanation:

From the information given, by applying Kepler's 3rd law,

$T^2 \alpha a^3$

where;

T = period

a = semi major axis

T = 356 days (for earth)

a = 1 AU = 1.496 $\times 10^8 \ km$

Therefore, $T^2 = ca^3$

$c= \dfrac{365^2}{(1.496 \times 10^8)^3}$

c = 3.9791 $\times 10^{20} \ day^2/km^3$

However, if the body in the solar system has a period of 10.759.22 days, then, a =?

∴

$T^2 = ca^3$

$a3 = \dfrac{10759.22^2}{3.9791 \times 10^{-20}}$

$a^3 = 2.9092 \times 10^{27}$

$a= \sqrt[3]{2.9092 \times 10^{27}}$

a = 1.4275 $\times 10^9 \ km$

However, the velocity for a perihelion = 10.18 km/s

Using the formula

$v = \sqrt{GM ( \dfrac{2}{r}-\dfrac{1}{a})}$ to calculate the radius, we have:

G = $6.674 \times 10^{-11}$

M = $1.989\times 10^{30} \ kg$

r = perihelion

$v ^2= GM ( \dfrac{2}{r}-\dfrac{1}{a})$

$(10.18 \times 10^3) ^2= 6.674 \times 10^{-11} \times 1.989 \times 10^{30} ( \dfrac{2}{r}-\dfrac{1}{1.425 \times 10^{12}})$

$7.8068 \times 10^{-13}= \dfrac{2}{r}-\dfrac{1}{1.425 \times 10^{12}}$

$\dfrac{2}{r} = 1.4824 \times 10^{-12}$

$r = \dfrac{2}{1.4824 \times 10^{-12}}$

$r = 1.349 \times 10^{12}$

Similarly, the perihelion is expressed by the equation,

r = a(1 - e)

where ;

e= eccentricity

∴

$1.349 \times 10^{12} = 1.425 \times 10^{12} ( 1 - e)$

$1.349 \times 10^{12} - 1.425 \times 10^{12}= - 1.425 \times 10^{12} (e)$

$-7.6\times 10^{10}= - 1.425 \times 10^{12} (e)$

$\dfrac{-7.6\times 10^{10}}{- 1.425 \times 10^{12}}= (e)$

e ( eccentricity) = 0.0533

Aphelion radius in natural miles, r = a( 1+ e)

$r = 1.425 \times 10^{12} ( 1 + 0.0533)$

$r = 1.50 \times 10^{12} \ m$

to nautical miles, we have:

$r = 1.50 \times 10^{12} \times 0.00054 \ nautical \ mile$

radius of aphelion $\mathbf{r = 8.10 \times 10^8}$ nautical miles

In respect to the value of a( i.e $1.4275 \times 10^9 \ km)$

the body of the solar system is Saturn

5 0

3 years ago

Define technology for class 7

Dafna1 [17]

Answer:

<h2>Required Answer :-</h2>

Technology - Technology is defined as the information about some thing. We may also use these technologies in our business

Ex :- Internet is a technology.

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8 0

2 years ago

Which of these channel members is last in the distribution channel?￼

Which of these channel members is last in the distribution channel?