here u go! i hope this is correct :)
Answer:
Rectangular area as a function of x : A(x) = 200*x + 2*x²
A(max) = 5000 m²
Dimensions:
x = 50 m
l = 100 m
Step-by-step explanation:
"x" is the length of the perpendicular side to the wall of the rectangular area to be fenced, and we call "l" the other side (parallel to the wall of the barn) then:
A(r) = x* l and the perimeter of the rectangular shape is
P = 2*x + 2*l but we won´t use any fencing material along the wll of the barn therefore
P = 2*x + l ⇒ 200 = 2*x + l ⇒ l = 200 - 2*x (1)
And the rectangular area as a function of x is:
A(x) = x * ( 200 - 2*x) ⇒ A(x) = 200*x + 2*x²
Taking derivatives on both sides of the equation we get:
A´(x) = 200 - 4*x ⇒ A´= 0
Then 200 - 4*x = 0 ⇒ 4*x = 200 ⇒ x = 50 m
We find the l value, plugging the value of x in equation (1)
l = 200 - 2*x ⇒ l = 200 - 2*50 ⇒ l = 100 m
A(max) = 100*50
A(max) = 5000 m²
Answer:
Step-by-step explanation:
4)
Given the expression
a+b-c
substituting the values in the expression
a+b-c = 4.1+5.7-0.3
= 9.8 - 0.3
= 9.5
5)
Given the expression
10-(a+b)
substituting the values in the expression
10-(a+b) = 10 - (4.1+5.7)
= 10 - 9.8
= 0.2
6)
Given the expression
b-c+2
substituting the values in the expression
b-c+2 = 5.7 - 0.3 +2
= 5.4 + 2
= 7.4
It’s the first one!! :)))
