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2 years ago

Pls help with this question

Mathematics

1 answer:

ser-zykov [4K]2 years ago

4 0

Answer:

2.01, 2, 2.1, 5, 7, 2.001, 3, 10

Step-by-step explanation:

That is a less greater than or equal to symbol, therefore the answer is any number that is 2, or greater than 2

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A lot of points for who gets this right!

tigry1 [53]

Answer:

on the end of the graph (5,10)

Step-by-step explanation:

hope that

5 0

2 years ago

rotation of 90 degrees counterclockwise about the origin, point O, then a reflection across the x-axis reflection across the y-a

SpyIntel [72]

Answer:

The point O can be (x,y) or (-x,y) or (-x,-y) or ( x,-y) reason being that you haven't given point O lies in which quadrant.

Rotation through 90° counter clockwise

(x,y) = (-y,x)

(-x,y)=(-y,-x)

(-x,-y)=(y,-x)

(x,-y) =(y,x)

Then Reflection across X axis has taken place.

(-y,x) = (-y,-x)

(-y,-x)=(-y,x)

(y,-x)=(y,x)

(y,x)=(y,-x)

Then a reflection across the y-axis has taken place.

(-y,-x)=(y,-x)

(-y,x) = (y,x)

(y,x) =(-y,x)

(y,-x)=(-y,-x)

Then a translation a units to the right and b units up has taken place.

(y,-x)=(y+a,-x+b)

(y,x) =(y+a, x+b)

(-y,x) =(-y+a,x+b)

(-y,-x)=(-y+a,-x+b)

Then a rotation of 180 degrees counterclockwise about the origin has taken place.

(y+a,-x+b)=[-(y+a),-(-x+b)]

(y+a, x+b)=[- (y+a), -(x+b)]

(-y+a,x+b)=[-(-y+a),-(x+b)]

(-y+a,-x+b) =[-(-y+a),-(-x+b)]

Now Again a reflection across the Y axis has taken place.

[-(y+a),-(-x+b)]=[(y+a),-(-x+b)]

[-(y+a),-(x+b)]=[(y+a),-(-x+b)]

[-(-y+a),-(x+b)]=[(-y+a),-(x+b)]

[-(-y+a),-(-x+b)]=[(-y+a),-(-x+b)]

Totally depends on value of a and b on which quadrant these point lies.

7 0

2 years ago

WILL GIVE BRAINLIEST IF CORRECT!!

vfiekz [6]

Answer:

$\displaystyle y=-0.927x+13.63$

Step-by-step explanation:

<u>Simple Linear Regression </u>

It a function that represents the relationship between two or more variables in a given data set. It uses the method of the least-squares regression line which minimizes the error between the estimate function and the real data.

Let's compute the best-fit line for the data

$x=\{1,5,6,12,15\}$

$y=\{14,11,4,2,1\}$

First, we find the sums

$\displaystyle \sum x=1+5+6+12+15=39$

$\displaystyle \sum y=14+11+4+2+1=32$

Then, we compute the averages values

$\displaystyle \bar{x}=\frac{39}{5}=7.8$

$\displaystyle \bar{y}=\frac{32}{5}=6.4$

We will also compute the sums of the cross-products and the sum of the squares

$\displaystyle \sum xy=(1)(14)+(5)(11)+(6)(4)+(12)(2)+(15)(1)=137$

$\displaystyle \sum x^2=1^2+5^2+6^2+12^2+15^2=1+25+36+144+225$

$\displaystyle \sum x^2=431$

We will compute Sxy and Sxx

$\displaystyle S_{xy}=\sum xy-\frac{\sum x\ \sum y}{n}$

$\displaystyle S_{xy}=137-\frac{(39)(32)}{5}$

$\displaystyle S_{xy}=-117.6$

$\displaystyle S_{xx}=\sum x^2-\frac{(\sum x)^2}{n}$

$\displaystyle S_{xx}=431-\frac{39}{5}^2=126.8$

The slope of the linear regression function is given by

$\displaystyle m=\frac{S_{xy}}{S_{xx}}=\frac{-117.6}{126.8}=-0.927$

The y-intercept ot the linear function is

$\displaystyle b=\bar{y}-b\bar{x}=6.4-(-0.927)(7.8)$

$\displaystyle b=13.63$

Thus the best-fit line is

$\displaystyle y=-0.927x+13.63$

The correct option is the last one

5 0

2 years ago

Solve for x in the equation x^2+4x-4=8

quester [9]

I will get you started.

x^2+4x-4 = 8

x^2 + 4x - 4 - 8 = 0

x^2 + 4x - 12 = 0

You must now use the quadratic formula.

In the formula, a = 1, b = 4, and c = -12.

Take it from here.

8 0

2 years ago

A wall clock is generally a more precise tool for measuring a length of time than a stopwatch.

Sergio039 [100]

Answer:

False

Step-by-step explanation:

8 0

2 years ago