Step 1: Subtract 50 from both sides.
<span><span><span>y+50</span>−50</span>=<span>200−50</span></span><span>y=150
</span><u>Answer:
</u><span>y=<span>150</span></span>
Answer:
In picture...
Step-by-step explanation:
I solved it step by step in picture. U can have a look
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Answer:
P ( 3, - pi/3 + 2 pi n) or P ( -3 , -pi/3 + pi(2 n +1))
Step-by-step explanation:
P ( 3, - pi/3)
We can circle 2pi n around the circle and be back at the same polar coordinate
P ( 3, - pi/3 + 2 pi n)
or we can flip the radius to a negative and add pi to the theta
P ( -3, - pi/3 + pi)
Then we can circle 2pi n around the circle and be back at the same polar coordinate
P ( -3 , -pi/3 + 2 pi n +pi)
P ( -3 , -pi/3 + pi(2 n +1))
Let x be the shorter side, and y be the longer side
There would be 4 fences along the shorter side, and 2 fences along the longer side
4x + 2y = 800
Rewrite in terms of y:
y = 400 − 2x
The area of the rectangular field is
A = x*y
Replace Y with the equation above:
A = x(400 − 2x)
A = − 2x^2 + 400x
The area is a parabola that opens downward, the maximum area would occur at the parabola vertex.
At the vertex
x = −b/2a
= −400/[2(−2)]
= 100
y = 400 −2x
y = 400 -2(100)
y = 400-200
y = 200
The dimension of the rectangular field that maximize the enclosed area is 100 ft x 200 ft.
