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WARRIOR [948]
3 years ago
15

Which would show an example of how physical changes are reversible?

Physics
2 answers:
kondor19780726 [428]3 years ago
8 0

Answer:

Melting tin and then cooling it into a mold

Explanation:

When you melt something, and when it cools it returns to its physical state, therefore the physical changes are reversible. For example, take chocolate. When chocolate melts its liquid, then when it's in a colder situation it becomes solid again and so on, the changes are reversible.

il63 [147K]3 years ago
8 0

Answer:

C

Explanation:

the physical change was the gold bar being cut and if it is put back together the physical change is reversed

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Principal of simple machine?​
sergij07 [2.7K]

Answer:

if there is no friction in a simple machine, work output and work input are found equal in that machine

Explanation:

3 0
3 years ago
Vector → A points due north and vector → B points due west. Both vectors have the same magnitude. Which of the following vectors
-BARSIC- [3]

Answer:

B - A

Explanation:

For the combination of 2 vector to due southwest, 1 vector must due south and the other vector due west. Since vector B is already due west, vector A should due south. As vector A is already due north, vector -A would due south. So the combination of B + (-A) or B - A should points southwest

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2 years ago
Jasper didn't want to help out with the dishes. He put off the task toward the end of the day. He even tried to get his
Temka [501]

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The last answer work avoident goal

8 0
2 years ago
A 9 newtwon charge is Felt on a (1x10^-4) C charge from another charge that is 3 meters away. What is the magnitude of that othe
Marina86 [1]

The magnitude of that other charge will be 9×10⁻⁵ C. The force on the charge is inverse of the distance.

<h3>What is Columb's law?</h3>

The force of attraction between two charges, according to Coulomb's law, is directly proportional to the product of the charges and inversely proportional to the square of the distance between them.

The magnitude of that other charge is found as;

\rm F = \frac{Kq_1q_2}{r^2} \\\\ \rm 9  = \frac{9 \times 10^9 \times 1\times 10^{-4}\times q_2}{(3)^2} \\\\ q_2=9\times 10^{-5} \ C

Hence, the magnitude of that other charge will be 9×10⁻⁵ C.

To learn more about Columb's law, refer to the link;

brainly.com/question/1616890

#SPJ1

6 0
2 years ago
If an airplane with a mass of 5 tons has gravitational potential energy of 1000 kilojoules, what is its height?
VLD [36.1K]
The gravitational potential energy of an object, measured with respect to the ground, is given by
U=mgh
where m is the object's mass, g is the gravitational acceleration and h is the height of the object measured from the ground.

In our problem, the mass of the plane is m= 5 tons = 5000 kg, while the potential energy is
U=1000 kJ=1 \cdot 10^6 J
so we can re-arrange the previous formula and use these data to calculate h, the height of the airplane:
h= \frac{U}{mg}= \frac{1 \cdot 10^6 J}{(5000 kg)(9.81 m/s^2)} =20.39 m
3 0
3 years ago
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