The gravitational force between two asteroids is 100N. What would the force be if the distance between the asteroids was cut in
half?
1 answer:
The gravitational forces between two masses are inversely proportional to
the square of the distance between the centers of the masses.
So if the distance between the <u>centers</u> of the asteroids is multiplied by 1/2,
then the gravitational forces between them are multiplied by ...
1 / (1/2)² = (2)² = 4 .
The new force is (100N) x (4) = <em>400N</em>.
You might be interested in
Answer:
D 7500
Explanation:
Energy is elastic potential energy
EPE=1/2 kx^2
6=1/2 k(0.04)^2
6=k (0.0016/2)
k = 6/0.0008 = 7500
Search it up and there’s a video of how to make spectroscope.
4A. PE = MxGxH. (You can consider g as 9.8 / 10m/s as well)
509 J = 12x10xH
509 J = 120xH
H = 509/120
H = 4.24 m
Hope u got the answer....pls rate the answer if it is helpful for u....and I'm sorry I could not understand B part so I didn't do it.
Thank you
The top of the trajectory is the point where it changes from rising to falling. At that exact instant, its vertical speed is zero.
2a) moment = 1.5P
2bi) 210*1 = 210Nm
2bii) 140N
2biii) 70 N