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Irina-Kira [14]
4 years ago
15

A point charge of 5.0 × 10–7 C moves to the right at 2.6 × 105 m/s in a magnetic field that is directed into the screen and has

a field strength of 1.8 × 10–2 T. What is the magnitude of the magnetic force acting on the charge? A. 0 N B. 2.3 × 10^–3 N C. 23 N D.2.3 × 10^11 N
The magnetic field 0.02 m from a wire is 0.1 T. What is the magnitude of the magnetic field 0.01 m from the same wire? A. 0.01 T B. 0.05 T C. 0.1 T D. 0.2 T
Physics
1 answer:
Over [174]4 years ago
9 0
1.) The formula for magnetic force is F = qvBsinθ.
Substituting, we have F=(5.0 × 10^–7 C) (2.6 × 10^5 m/s) (1.8 × 10^–2 T)(sin90°) [90° because point charge is perpendicular to magnetic field]

F = 2.34 x 10^-3 N
Answer is B.

2.) <span>The distance is reduced by 1/2, so B is twice or 0.2 T. Answer is D.</span>
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Andru [333]
First, we need to find the number of protons, which is the total mass divided by the mass of one proton:
N= \frac{m}{m_p}= \frac{1.0 kg}{1.67 \cdot 10^{-27} kg}=6.0 \cdot 10^{26} protons

Then, the total charge is the number of protons times the charge of a  single proton:
Q=Ne = 6.0 \cdot 10^{26}\cdot 1.60 \cdot 10^{-19} C=9.6 \cdot 10^7 C
8 0
3 years ago
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This formula equation is unbalanced.
Grace [21]
The answer is:  [C]:  "4" .
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The balanced equation is:
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6 0
3 years ago
Consider the interactions involved when you use a TV remote control to change the channel. Classify each interaction as long ran
makvit [3.9K]

Explanation:

Following are two interactions that are generally involved when we use a TV remote control to change the channel :

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7 0
3 years ago
A jet airliner moving initially at 406 mph (with respect to the ground) to the east moves into a region where the wind is blowin
astraxan [27]

Answer:

966 mph

Explanation:

Using as convention:

- East --> positive x-direction

- North --> Positive y-direction

The x- and y- components of the initial velocity of the jet can be written as

v_{1x} = 406 mph\\v_{1y} = 0

While the components of the velocity of the wind are

v_{2x} = (568)(cos 15^{\circ})=548.6 mph\\v_{2y} = (568)(sin 15^{\circ})=147.0 mph

So the components of the resultant velocity of the jet are

v_x = v_{1x}+v_{2x}=406+548.6=954.6 mph\\v_y = v_{1y}+v_{2y}=0+147.0=147.0 mph

And the new speed is the magnitude of the resultant velocity:

v=\sqrt{v_x^2+v_y^2}=\sqrt{(954.6)^2+(147.0)^2}=965.8 mph \sim 966 mph

6 0
3 years ago
Match the measurements to the correct number of significant figures.
Shalnov [3]
To calculate the number of sig figs
1.  Count ALL nonzero numbers
2.  If the zero is between 2 numbers, count it
3.  If in a decimal the zero is at the end, count it
4.  In a decimal all the zeros before the first nonzero number are placeholders and don't count them
5.  In a number greater than zero all zeros AFTER the last nonzero number are placeholders and don't count them.

A - 5
B - 2
C - 3
D - 1
E - 4
8 0
3 years ago
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