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Irina-Kira [14]
4 years ago
15

A point charge of 5.0 × 10–7 C moves to the right at 2.6 × 105 m/s in a magnetic field that is directed into the screen and has

a field strength of 1.8 × 10–2 T. What is the magnitude of the magnetic force acting on the charge? A. 0 N B. 2.3 × 10^–3 N C. 23 N D.2.3 × 10^11 N
The magnetic field 0.02 m from a wire is 0.1 T. What is the magnitude of the magnetic field 0.01 m from the same wire? A. 0.01 T B. 0.05 T C. 0.1 T D. 0.2 T
Physics
1 answer:
Over [174]4 years ago
9 0
1.) The formula for magnetic force is F = qvBsinθ.
Substituting, we have F=(5.0 × 10^–7 C) (2.6 × 10^5 m/s) (1.8 × 10^–2 T)(sin90°) [90° because point charge is perpendicular to magnetic field]

F = 2.34 x 10^-3 N
Answer is B.

2.) <span>The distance is reduced by 1/2, so B is twice or 0.2 T. Answer is D.</span>
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A 0.5 kg baseball is hit by a bat delivering an impulse of 180 kg x m/s. If the bat is in contact with the baseball for 0.4 seco
yan [13]

Answer:

450N

Explanation:

Impulse = mv    --->   180kgm/s = (0.5kg)v

v = 360 m/s

Acceleration = v/t    --->   a = (360 m/s)/(0.4s) = 900 m/s^2

Force = ma   --->   F = (0.5kg)(900 m/s^2) = 450N

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3 years ago
What is thermal energy defined as
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Answer:

hermal energy is the energy that is generated and measured by heat. 

8 0
3 years ago
Read 2 more answers
a 1.5 kg ball is thrown vertically upward with an initial speed of 15 m/s. if the initial potential energy is taken as zero, fin
trapecia [35]

Answer:

a) E_{p} = 0

E_{k} = 168.7 J

E_{m} = 168.7 J

b) E_{p} = 73.6 J

E_{k} = 95.8 J

E_{m} = 169.4 J

c) E_{p} = 169.2 J

E_{k} = 0

E_{m} = 169.2 J

Explanation:

We have:

m: is the ball's mass = 1.5 kg

v₀: is the initial speed = 15 m/s

g: is the gravity acceleration = 9.81 m/s²

a) In the initial position we have:

h: is the height = 0

The potential energy is given by:

E_{p} = mgh = 0

The kinetic energy is:

E_{k} = \frac{1}{2}mv^{2} = \frac{1}{2}*1.5*(15)^{2} = 168.7 J

And the mechanical energies:

E_{m} = E_{p} + E_{k} = 0 + 168.7 J = 168.7 J

b) At 5 m above the initial position we have:

h = 5 m

The potential energy is:

E_{p} = mgh = 1.5*9.81*5 = 73.6 J

Now, to find the kinetic energy we need to calculate the speed at 5 m:

v_{f}^{2} = v_{0}^{2} - 2gh = (15)^{2} - 2*9.81*5 = 126.9

v_{f} = \sqrt{126.9} = 11.3 m/s

E_{k} = \frac{1}{2}mv^{2} = \frac{1}{2}*1.5*(11.3)^{2} = 95.8 J

And the mechanical energies:

E_{m} = E_{p} + E_{k} = 73.6 + 95.8 J = 169.4 J

c) At its maximum height:

v_{f}: is the final speed = 0

h = \frac{v_{0}^{2}}{2g} = \frac{(15)^{2}}{2*9.81} = 11.5 m

Now, the potential, kinetic and mechanical energies are:

E_{p} = mgh = 1.5*9.81*11.5 = 169.2 J

E_{k} = \frac{1}{2}mv^{2} = 0

E_{m} = 169.2 J + 0 = 169.2 J

I hope it helps you!    

7 0
3 years ago
The fact that the magnetic field generates a force perpendicular to the instantaneous velocity of the particle has implications
Anna35 [415]

Answer:

<h2>c. remain constant</h2>

Explanation:

Such type of field that is created by the magnetic condition is known as magnetic field. Such type of the developed by electrical condition and some other ways. This filed has many important roles in electrical engineering and some other fields.  

When any magnetic field acts in perpendicular condition then no work is done by the field. Thus the kinetic energy and speed of the particle remain in constant condition.

3 0
3 years ago
What force is required to accelerate a body with a mass of 15 kilograms at a rate of 8 m/s²?
lawyer [7]

I really think it could be a 23 kg

4 0
4 years ago
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