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Triss [41]
3 years ago
5

A mass of 2.8 kg lies on a frictionless table,

Physics
1 answer:
Greeley [361]3 years ago
6 0

Answer:

17.15 m/s²

Explanation:

The formula for force is ;

F= m*a   where m is mass of object 1 and a is acceleration due to gravity

The force, F , used in pulling the mass is ;

4.9 * 9.8 =48.02 N

Applying the formula for force to get acceleration

F= m*a

48.02 = 2.8 * a

a= 48.02 / 2.8

a= 17.15 m/s²

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Your answer is Gravity


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5 0
3 years ago
Determine the approximate force (N) used to pull a sled up a 400 m hill using 1900 J of work.
Sergeu [11.5K]
The work done to pull the sled up to the hill is given by
W=Fd
where
F is the intensity of the force
d is the distance where the force is applied.

In our problem, the work done is W=1900 J and the distance through which the force is applied is d=400 m, so we can calculate the average force by re-arranging the previous equation and by using these data:
F= \frac{W}{d}= \frac{1900 J}{400 m} = 4.75 N \sim 5 N
4 0
4 years ago
If y = 0.02 sin (30x – 200t) (SI units), the frequency of the wave is
leva [86]

Answer:

31.831 Hz.

Explanation:

<u>Given:</u>

  • \rm y = 0.02\sin(30x-200 t).

The vertical displacement of a wave is given in generalized form as

\rm y = A\sin(kx -\omega t).

<em>where</em>,

  • A = amplitude of the displacement of the wave.
  • k = wave number of the wave = \dfrac{2\pi }{\lambda}.
  • \lambda = wavelength of the wave.
  • x = horizontal displacement of the wave.
  • \omega = angular frequency of the wave = \rm 2\pi f.
  • f = frequency of the wave.
  • t = time at which the displacement is calculated.

On comparing the generalized equation with the given equation of the displacement of the wave, we get,

\rm A=0.02.\\k=30.\\\omega =200.\\

therefore,

\rm 2\pi f=200\\\\\Rightarrow f = \dfrac{200}{2\pi}=31.831\ Hz.

It is the required frequency of the wave.

3 0
3 years ago
How Can the human ear detect the sound
liq [111]

Explanation:

The eardrum vibrates from the incoming sound waves and sends these vibrations to three tiny bones in the middle ear. These bones are called the malleus, incus, and stapes.

8 0
3 years ago
A hummingbird can flutter its wings 4,800 times per minute.
Marianna [84]
80 flutters per second
4 0
3 years ago
Read 2 more answers
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