Answer:
t=67.7s
Explanation:
From this question we know that:
Vo = 6m/s
a = 1.8 m/s2
D = 1500m
And we also know that:
Replacing the known values:
Solving for t we get 2 possible answers:
t1 = -44.3s and t2 = 67.7s Since negative time represents an instant before the beginning of the movement, t1 is discarded. So, the final answer is:
t = 67.7s
This type of a problem can be solved by considering energy transformations. Initially, the spring is compressed, thus having stored something called an elastic potential energy. This energy is proportional to the square of the spring displacement d from its normal (neutral position) and the spring constant k:

So, this spring is storing almost 12 Joules of potential energy. This energy is ready to be transformed into the kinetic energy when the masses are released. There are two 0.2kg masses that will be moving away from each other, their total kinetic energy after the release equaling the elastic energy prior to the release (no losses, since there is no friction to be reckoned with).
The kinetic energy of a mass m moving with a velocity v is given by:

And we know that the energies are conserved, so the two kinetic energies will equal the elastic potential one:

From this we can determine the speed of the mass:

The speed will be 7.74m/s in in one direction (+), and same magnitude in the opposite direction (-).
Answer: Fourth option. It increased by a factor of 3.
Solution:
m1=1.0 kg
Cylinder's gravitational potential energy: Ep=m*g*h
Ep1=(1.0 kg)*g*h
Ep1=g*h
m2=3.0 kg
Ep2=(3.0 kg)*g*h
Ep2=3*g*h
Replacing g*h by Ep1 in the equation above:
Ep2=3*Ep1
Then, the cylinder's gravitational potential energy increased by a factor of 3.
Absolute, Atmospheric, Differential, and Gauge Pressure