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3 years ago

11

50 POINTS! You need to simply the equation below, please answer quick, deleting in 15 min

1 answer:

Iteru [2.4K]3 years ago

4 0

The answer is: $\frac{1}{x}$ .

I'll attach a photo with my work below. Have a good day, and good luck on your assignment! :)

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Write at least 5 names for 1/4

Elina [12.6K]

1.) One-Fourth
2.) One Quarter
3.) Two- Eighth
I can't think of any more :[ Hope this helped!!

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3 years ago

Plzzzz help give brain least

pshichka [43]

Answer:

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Step-by-step explanation:

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3 years ago

Which graph represents the function h(x) = 1x1 + 0.5?

slamgirl [31]

Answer:Top right

Step-by-step explanation:

Because they are all the same V shape, we look to the slope for the answer.

Because the Y-intercept in this equation is 0.5, we look for the graph in which it is centered and at 0.5

That would be the top right.

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2 years ago

Read 2 more answers

If the orientation of two shapes is not the same, which transformation(s) should you use to show they are congruent? Why?

nataly862011 [7]

Answer:

the amount of sides, angels and sides that are parellel.

Step-by-step explanation:

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3 years ago

Read 2 more answers

A magician’s stage has a rectangle trapdoor which is (x+ 1/2) by 2x ft. The outside rectangle length is (x+ 16) ft.

Katen [24]

Answer:

Part A:- $x +11 ft$ Part B:- $(4x+54)ft$ part C:- $x= 2ft$

Part D:- Yes it satisfy his requirement

Step-by-step explanation:

Given that,

length and breadth of Trapdoor are $(x+ \frac{1}{2} ) by 2x$ ft.

The Outside length of Rectangle is $(x+16 )$ ft.

Part A:- Total area (in square feet) of the stage can be represented by

$x^{2} + 27x+ 176$ . Write an expression for the width of stage.

So, Area of rectangle = $length \times breadth$

$x^{2} + 27x+ 176 = (x+16) \times breadth$

$Breadth = \frac{x^{2} + 27x+ 176}{x+16}$

$Breadth = x+11$ ft. ................(1)

Part B:- Write an expression for the Perimeter of the stage.

Here, Perimeter of Rectangle = $2(L+B)$

= $2(x+16 + x +11)$

= $(4x + 54) ft$

Part C:- The area of trapdoor is $10 ft^{2}$ . Find the value of x.

So, Area of trapdoor = $10 ft^{2}$

$(x +\frac{1}{2}) \times 2x =10 ft^{2}$

$2x^{2} +x - 10 = 0$

$x = \frac{-1-9}{4}$ , $\frac{-1+9}{4}$

$x = \frac{-5}{2}$ , $2$

Hence value of x is $2 ft$ (Neglecting the negative value because

length cannot be negative).

Part D:- The magician wishes to have the area of the stage be at least 20 times the area of the trapdoor. Does this stage satisfy his requirement? Explain.

So, Length of trapdoor is $(2+\frac{1}{2} ) = \frac{5}{2} ft$

breadth of trapdoor is $2\times 2 = 4ft$

Now, outside length of Rectangle is = $18ft$

And outside breadth of rectangle is = $13ft$

Here, Area of trapdoor = $\frac{5}{2} \times 4 = 10ft^{2}$ ...................(2)

Area of rectangle = $18 \times 13= 234 ft^{2}$ ....................(3)

Thus comparing Equation (1) & (2) we found that

Area of rectangular stage is 20 times greater than the area of trapdoor.

7 0

4 years ago