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sammy [17]
2 years ago
5

If an elephant has a net force of 10000 N downward while experiencing an upward force of 9000 N from air resistance, what is the

elephant's gravitational force downward?
-1000 N, downward
-20000 N, downward
-19000 N, downward
-0 N, the forces are balanced
Physics
1 answer:
Feliz [49]2 years ago
6 0

Explanation:

net \: force \:  = gravitation \: force - resistance \\ 10000 = F - 9000 \\ F = 19000

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A 2.00-m long uniform beam has a mass of 4.00 kg. The beam rests on a fulcrum that is 1.20 m from its left end. In order for the
Shalnov [3]

Answer:

x ’= 1,735 m,  measured from the far left

Explanation:

For the system to be in equilibrium, the law of rotational equilibrium must be fulfilled.

Let's fix a reference system located at the point of rotation and that the anticlockwise rotations have been positive

             

They tell us that we have a mass (m1) on the left side and another mass (M2) on the right side,

the mass that is at the left end x = 1.2 m measured from the pivot point, the mass of the right side is at a distance x and the weight of the body that is located at the geometric center of the bar

           x_{cm} = 1.2 -1

          x_ {cm} = 0.2 m

          Σ τ = 0

          w₁ 1.2 + mg 0.2 - W₂ x = 0

          x = \frac{m_1 g\ 1.2 \ + m g \ 0.2}{M_2 g}

          x = \frac{m_1 \ 1.2 \ + m \ 0.2 }{M_2}

let's calculate

          x = \frac{2.9 \ 1.2 \ + 4 \ 0.2 }{8.00}2.9 1.2 + 4 0.2 / 8

           

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measured from the pivot point

measured from the far left is

           x’= 1,2 + x

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3 years ago
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3 years ago
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Ratling [72]

Answer:

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8 0
3 years ago
A charge of Q is fixed in space. A second charge of q was first placed at a distance r1 away from Q. Then it was moved along a s
topjm [15]

Answer:

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7 0
3 years ago
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