Well I know two million are replaced each second I think I'm in fifth grade so ok this stuff lol
The applications, either for diagnostic purposes or for therapeutic purposes, involve the use of X-rays----CT scan radiography ,external beam radiation therapy, fluoroscopy.
How is CT used for treatment planning?
CT planning enables more accurate localisation of both tumour and normal organs in addition to providing an accurate body contour and inhomogeneity corrections.
What is difference between CT scan and fluoroscopy?
Overall, fluoroscopy is a safe procedure, but potential risks include burns or radiation-induced injuries to the skin. On the other hand, CT scans are still snapshots of a “slice” of the body. They use X-rays to help your doctor view important organs
What is a fluoroscopic procedure?
During a fluoroscopy procedure, an X-ray beam is passed through the body. The image is transmitted to a monitor so the movement of a body part or of an instrument or contrast agent (“X-ray dye”) through the body can be seen in detail
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There are 3 bases before you reach home plate.
Answer:When the ball rolls off the edge of the table, it will continue moving forward at 2.0 m/s until it hits the floor.
Explanation:This is what I would say is the answer bc I had to do reasearch on a lot of this for my work this year so if its not im veery sorry
Answer:
The new Coulomb force is q₁q₂/9πε₀r²
Explanation
The coulomb force between the two charges q₁ and q₂ at a distance r in air is given by F = q₁q₂/4πε₀r².
Now, let us assume the material of dielectric constant κ = 9 is placed between them on the side of the q₁ charge. The value of its effective charge is now q₃ = q₁/κ at a distance of d = r/2 from the q₂ charge.
Since we have air between q₂ and q₃, the coulomb force between them is
F' = q₂q₃/4πε₀d²
= q₂(q₁/κ)/4πε₀(r/2)²
= 4q₂q₁/κ4πε₀r²
= 4/κ(q₂q₁/4πε₀r²)
= 4/9 × (q₂q₁/4πε₀r²)
= q₁q₂/9πε₀r²
So, the new Coulomb force is q₁q₂/9πε₀r²