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Liono4ka [1.6K]
3 years ago
4

Etching is a process for producing images on metal plates that can be copied using a printing press. First, the metal plate is c

oated in a layer of wax. Next, an artist creates the image by scratching lines in the wax to reveal the metal. Finally, the plate is dipped in a liquid called the mordant, which eats away at the metal where the wax has been scraped away. This leaves an engraving in the plate that can pick up ink for printing. To break down the metal plate, the mordant should be composed of a(n) substance.
Physics
2 answers:
hjlf3 years ago
6 0

Answer:

acidic

Explanation:

Fed [463]3 years ago
3 0

Answer: The answer is acidic  

Explanation:

because did the test

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A star is moving toward the earth at 250 km/s. What can you say about the wavelength of the h-alpha absorption line that you wou
Juli2301 [7.4K]

The wavelength of the h-alpha absorption line that you would detect in the star's spectrum will be 54.67 *  10^{-2} nm

If the object is moving towards or away from us with some radial velocity, shifts can be observed in the location of the absorption

since, material is moving towards us  a shift to shorter wavelength will be observed

shift = rest wavelength * ( radial velocity / speed of light )

        = 656 * 10^{-9} * (250 * 10^{3}  / 3 * 10^{8} )

        = 54.67 *  10^{-2} nm

The wavelength of the h-alpha absorption line that you would detect in the star's spectrum will be 54.67 *  10^{-2} nm

learn more about radial velocity:

brainly.com/question/22409504?referrer=searchResults

#SPJ4

6 0
2 years ago
How many rings does saturn have
Colt1911 [192]

Answer:

From far away, Saturn looks like it has seven large rings. Each large ring is named for a letter of the alphabet. The rings were named in the order they were discovered.

3 0
3 years ago
The figure below shows a combination of capacitors. Find (a) the equivalent capacitance of combination, and (b) the energy store
velikii [3]

Answer:

A) C_{eq} = 15 10⁻⁶  F,  B)   U₃ = 3 J,  U₄ = 0.5 J

Explanation:

In a complicated circuit, the method of solving them is to work the circuit in pairs, finding the equivalent capacitance to reduce the circuit to simpler forms.

In this case let's start by finding the equivalent capacitance.

A) Let's solve the part where C1 and C3 are. These two capacitors are in serious

         \frac{1}{C_{eq}} = \frac{1}{C_1} + \frac{1}{C_3}            (you has an mistake in the formula)

         \frac{1}{C_{eq1}} = (\frac{1}{30} + \frac{1}{15}) \  10^{6}

         \frac{1}{C_{eq1}} = 0.1   10⁶

         C_{eq1} = 10 10⁻⁶ F

capacitors C₂, C₄ and C₅ are in series

          \frac{1}{C_{eq2}} = \frac{1}{C_2} + \frac{1}{C_4} + \frac{1}{C_5}

          \frac{1}{C_{eq2} }  = (\frac{1}{15} + \frac{1}{30} +   \frac{1}{10} ) \ 10^6

          \frac{1}{C_{eq2} } = 0.2 10⁶

          C_{eq2} = 5 10⁻⁶ F

the two equivalent capacitors are in parallel therefore

          C_{eq} = C_{eq1} + C_{eq2}

          C_{eq} = (10 + 5) 10⁻⁶

          C_{eq} = 15 10⁻⁶  F

B) the energy stored in C₃

The charge on the parallel voltage is constant

is the sum of the charge on each branch

         Q = C_{eq} V

         Q = 15 10⁻⁶ 6

         Q = 90 10⁻⁶ C

the charge on each branch is

         Q₁ = Ceq1 V

         Q₁ = 10 10⁻⁶ 6

          Q₁ = 60 10⁻⁶ C

         Q₂ = C_{eq2} V

         Q₂ = 5 10⁻⁶ 6

         Q₂ = 30 10⁻⁶ C

now let's analyze the load on each branch

Branch C₁ and C₃

           

In series combination the charge is constant    Q = Q₁ = Q₃

          U₃ = \frac{Q^2}{2 C_3}

          U₃ =\frac{ 60 \ 10^{-6}}{2 \ 10 \ 10^{-6}}

          U₃ = 3 J

In Branch C₂, C₄, C₅

since the capacitors are in series the charge is constant Q = Q₂ = Q₄ = Q₅

          U₄ = \frac{30 \ 10^{-6}}{ 2 \ 30 \ 10^{-6}}

          U₄ = 0.5 J

7 0
3 years ago
A train is travelling along a straight track at constant velocity from Western Station to Eastern station. The mile markers incr
S_A_V [24]

Answer:

Explanation:

Displacement of train = 60 - 25 = 35 mile

= 35 x 1.6 = 56 km

duration of time = 45 - 15 = 30 minutes

= 30 x 60 = 1800 s

velocity of train = displacement / time

= 56 / 1800 = .03111 km /s

= 31.111 m / s

3 0
3 years ago
The density of mercury, the only metal to exist as a liquid at room temperature, is 13.6 g/cm3. what is that density in pounds p
Oxana [17]
Answer:<span>222.86 g/inch</span>
The density is count by dividing mass by volume. In this case, the volume is changed from cm3 into cubic inch. First, you need to convert cm3 to cubic inch, which was 1cm3= 0.0610237 cubic inch. 
Then the calculation will be 13.6g/0.0610237 cubic inch= 222.864231438
6 0
3 years ago
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