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Lelu [443]
3 years ago
5

Calculate the recoil velocity of a rifle with a mass of 5.00 kg (including the bullet) after it fires a 0.005 kg bullet at a spe

ed of 300 m/s ?
Physics
1 answer:
Sidana [21]3 years ago
3 0

Given :

Velocity of bullet, v_b=300\ m/s.

Mass of bullet, m = 0.005 kg.

Mass of rifle, M = 5 kg.

To Find :

The recoil velocity of the rifle.

Solution :

Since, their is no external force is acting.

So, momentum of the system will be conserved :

Initial momentum = Final momentum

m(0) + M(0) = m(300) + Mv

v=-\dfrac{300m}{M}\\\\v=-\dfrac{300\times 0.005}{5}\\\\v=-0.3 \ m/s

Therefore, recoil velocity of the rifle is 0.3 m/s.

Hence, this is the required solution.

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The position of an object as a function of time is given by x = bt 2 - ct, where b = 2.0 m/s2 and c = 6.7 m/s, and x and t are i
nika2105 [10]

Answer:

The instantaneous velocity of the object when t = 4.1 is 9.7 \frac{m}{s}.

Explanation:

Instantaneous velocity, v = \frac{dx}{dt}

x = b t^{2} - ct

v = \frac{dx}{dt} = 2bt - c

At t = 4.1 s

v = 2 × b × 4.1 - c

b = 2.0 \frac{m}{s^{2} }

c = 6.7 \frac{m}{s} ...(Given)

v = 2 × 2 × 4.1 - 6.7

v = 9.7 \frac{m}{s}

The instantaneous velocity of the object when t = 4.1 is 9.7 \frac{m}{s}.


3 0
3 years ago
Based on what you know, please list at least 4 characteristics of weather. IDK IF RIGHT SUBJECT
Bas_tet [7]
Rain sleet hail and snow
5 0
3 years ago
A dogsled is moving at a constant speed of 3.0 m/s in a straight line on level ground,
denis-greek [22]

Answer:

0 N

Explanation:

The key for solving the problem is in the sentence "moving at a constant speed in a straight line".

In fact, this means that the velocity of the sled is constant: and therefore, that its acceleration.

Newton's second law states that:

F = ma

where

F is the net force on an object

m is its mass

a is its acceleration

In this problem, we have asserted that the acceleration of the sled is zero:

a = 0

Therefore, according to the equation above, this also means that the net force on the sled is also  zero:

F = 0 N

(This implies that there must be another force, must like the force of friction, that acts backward, in the opposite direction to the pull applied by the dogs).

6 0
3 years ago
The 50-mm-diameter cylinder is made from Am 1004-T61 magnesium and is placed in the clamp when the temperature is T1 = 15°C. If
Sergio [31]

Answer:

The temperature of steel first becomes 12 MPa at a temperature of 18.65°C

Explanation:

Given that,

Diameter = 50 mm

Temperature = 15°C

Diameter = 10 mm

Stress = 12 MPa

We need to calculate the temperature of steel

Using formula of stress

stress=\alpha Y\Delta T

Where, Y = young modulus

T = temperature

\alpha= coefficient of linear expansion of the material

Put the value into the formula

12\times10^{6}=17.3\times10^{-6}\times190\times10^{9}\times(T_{2}-15)

(T_{2}-15)=\dfrac{12\times10^{6}}{17.3\times10^{-6}\times190\times10^{9}}

T_{2}=3.650+15

T_{2}=18.65^{\circ}

We need to calculate the temperature of magnesium

Using formula of  stress

stress=\alpha Y\Delta T

Put the value into the formula

12\times10^{6}=25.2\times10^{-6}\times45\times10^{9}\times(T_{2}-15)

(T_{2}-15)=\dfrac{12\times10^{6}}{25.2\times10^{-6}\times45\times10^{9}}

T_{2}=10.5+15

T_{2}=25.58^{\circ}

Hence, The temperature of steel first becomes 12 MPa at a temperature of 18.65°C

7 0
3 years ago
SUBJECT: ASTRONOMY -- TOPIC: Time Dilation
inessss [21]

Answer:

You can determine if the ship is moving by lying down and measuring your height.

Explanation:

3 0
3 years ago
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