<span>Molecular mass of C is: 12.01 g/mol
1 mole C: 0.012 kg
Molecular mass of H is: 1.08 g/mol
1 mole H: 0.01 kg
Reduced mass: Mr = m1m2/(m1+m2) = 0.012*0.01/(0.022) = 5.45x10-³ kg
f = (1/2π)√(k/Mr) = (1/2π)√{500/5.45x10-³} = (1/2π)10²√{9.166} = 48.1 Hz. I hope this helps </span>
<h2>K.E/P.E = m/k tan²φ x ω²</h2>
Explanation:
The given position of block x = x₀ cos(ωt + φ)
The velocity of block v = dx/dt = - x₀ sin(ωt + φ) x ω
The kinetic energy = 1/2 mv² = 1/2 m x₀² sin²(ωt + φ) x ω²
The potential energy of spring = 1/2 k x² , where k is the spring constant
Thus P.E = 1/2 x k x x₀² cos²(ωt + φ)
When t = 0
K.E = 1/2 m x₀²sin²φ x ω²
P.E = 1/2 k x₀² cos²φ
Dividing these , we have
K.E/P.E = m/k tan²φ x ω²
Answer:
<em>Radiation is energy that comes from a source and travels through space and may be able to penetrate various materials. Light, radio, and microwaves are types of radiation that are called nonionizing.</em>
Explanation:
Explanation:
10
/9 Ω
potential difference across the cell in open circuit is the emf of the cell.
Hence, emf E=2.2V
when, circuit is closed, potential difference across cell is given by V=E−Ir
And,
I= E/
R+r
Hence, V= E− Er/
R+r
⟹ V= ER/
R+r
⟹ 1.8= 2.2×5
/5+r
⟹9+1.8r=11
⟹ r= 2/ 1.8 Ω
⟹ r= 10/9 Ω
Answer:
A combustion reaction is a major class of chemical reactions, commonly referred to as "burning." In the most general sense, combustion involves a reaction between any combustible material and an oxidizer to form an oxidized product. It usually occurs when a hydrocarbon reacts with oxygen to produce carbon dioxide and water. Good signs that you're dealing with a combustion reaction include the presence of oxygen as a reactant and carbon dioxide, water, and heat as products. Inorganic combustion reactions might not form all of those products but remain recognizable by the reaction of oxygen.
Explanation: