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3 years ago

What two factors affect the strength of a magnetic field

Physics

1 answer:

Stels [109]3 years ago

7 0

Answer:

Factors Affecting the Strength of the Magnetic Field of an Electromagnet: Factors that affect the strength of electromagnets are the nature of the core material, strength of the current passing through the core, the number of turns of wire on the core and the shape and size of the core.

Explanation:

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Help please <br><br> Gravitation

xxMikexx [17]

Answer:a force of attraction exerted by each particle of matter in the universe on every other particle

Explanation:gravitation describes the attractive force between any two masses

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3 years ago

An ocean current moving from the equator toward a pole is

Viefleur [7K]

Answer:

A warm current

Explanation:

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3 years ago

Read 2 more answers

An open-end mercury manometer is connected to a low-pressure pipeline that supplies a gas to a laboratory. Because paint was spi

Svetllana [295]

Answer:

$P_G = 14.03 \ psig$

$h_m = 0.148 \ m$

Explanation:

From the question we are told that

The pressure of the manometer when there is no gas flow is $P_{m} = 15.5 \ psig = 15.5 * 6894.76 = 106868.78 \ N/m^2$

The level of mercury is $h = 950 \ mm = 0.950 \ m$

The drop in the mercury level at the visible arm is $d = 39.0 = 0.039 \ m$

Generally when there is no gas flow the pressure of the manometer is equal to the gauge pressure which is mathematically represented as

$P_g = P_m = g * \delta h * \rho$

Here $\rho$ is the density of mercury with value $\rho = 13.6 *10^{3} kg/m^3$

and $\delta h$ is the difference in the level of gas in arm one and two

$\delta h = \frac{106868.78}{ 13.6 *10^{3} * 9.8 }$

$\delta h = 0.802 \ m$

Generally the height of the mercury at the arm connected to the pipe is mathematically represented as

$h_m = 0.950 - 0.802$

=> $h_m = 0.148 \ m$

Generally from manometry principle we have that

$P_G + \rho * g * d - \rho * g * [h - (h_m + d)] = 0$

Here $P_G$ is the pressure of the gas

$P_G +13.6 *10^{3} * 9.8 * 0.039 - 13.6 *10^{3} * 9.8 * [0.950 - (0.148 + 0.039)] = 0$

$P_G = 9.6724 04 *10^{4} \ N/m^2$

converting to psig

$P_G = \frac{ 9.6724 04 *10^{4} }{6894.76}$

$P_G = 14.03 \ psig$

6 0

3 years ago

Calculate the force of an 8kg object pushing up from the table

zepelin [54]

The correct answer to the question is: 78.4 N.

CALCULATION:

As per the question, the mass of the object is given as m = 8 Kg.

We are asked to calculate the force of 8 Kg object pushing up from the table.

The force pushing up from the table is nothing else than the normal reaction.

The normal reaction of the object is equal to the weight of the object as the object is simply resting on the table.

Hence, normal reaction = Weight

= mg

= 8 × 9.8 N.

= 78.4 N.

Here, g is known as acceleration due to gravity.

Hence, the force of the object pushing up from the table is 78.4 N.

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4 years ago

What change takes place in a wave when the frequency of the wave increases?

Musya8 [376]

The answer is C. As the frequency of the waves increases, a greater number of wavelengths pass a given point per second. From the wave formula, we see that there is an indirect relationship between frequency and the wavelength. thus, as the frequency increases the wavelength decreases resulting to a smaller distance between the waves which will show greater number of wavelengths between waves.

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3 years ago