A certain wire, 3 m long, stretches by 1.2 mm when under tension of 200 N. By how much does an equally thick wire 6 m long, made of the same material and under the same tension, stretch?
2 answers:
Answer:
2.4 mm
Explanation:
Given that:
Initial Original length of the wire L = 3 mm
The stretch of the first wire ΔL= 1. 2 mm
The length of the second wire L'' = 6 mm
The stretch of the second wire ΔL'' = ???
Considering the Tension of the system; the Young modulus and the cross sectional remains constant ; as such:
Thus, the same material under the same tension stretches 2.4 mm
Answer:
2.4 mm
Explanation:
Given that
Length of the wire, L = 3 m
Extensión of the wire, ΔL = 1.2 mm = 1.2*10^-3 m
Tensión of wire, T = 200 N
We use the formula
Y = TL/ΔLA
Since both wires material is same that makes the value of young's modulus the same in both the cases
hence equating
[200 * 3 / 1.2*10^-3 * A] = [200 * 6 / ΔL * A]
ΔL = 2.4*10^-3 m = 2.4 mm
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