A certain wire, 3 m long, stretches by 1.2 mm when under tension of 200 N. By how much does an equally thick wire 6 m long, made
2 answers:
Answer:
2.4 mm
Explanation:
Given that:
Initial Original length of the wire L = 3 mm
The stretch of the first wire ΔL= 1. 2 mm
The length of the second wire L'' = 6 mm
The stretch of the second wire ΔL'' = ???
Considering the Tension of the system; the Young modulus and the cross sectional remains constant ; as such:
Thus, the same material under the same tension stretches 2.4 mm
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Answer:
1) The maximum jump height is reached at A.
2) The maximum center of mass height off of the ground is B.
3) The time of flight is C.
4) The distance of jump is B.
Explanation:
First of all we need to decompose velocity in its rectangular components, so
1) We use, , as we clear it for
and using the fact that
at max height, we obtain
2) We can use the formula for
, so
3) We can use the formula , to find total time of fligth, so
, as it is a second-grade polynomial, we find that its positive root is
4) Finally, we use , as it has an additional displacement of
due the leg extension we obtain,
, aprox