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shusha [124]
3 years ago
14

Two uniform solid spheres of the same size, but different mass, are released from rest simultaneously at the same height on a hi

ll and roll to the bottom without slipping. Part A Which of the following statements about these spheres are true?
A. Both spheres reach the bottom at the same time.
B. The heavier sphere reaches the bottom ahead of the lighter one.
C. Both spheres arrive at the bottom with the same forward speed.
D. Both spheres arrive at the bottom with the same total kinetic energy.
Physics
1 answer:
SpyIntel [72]3 years ago
4 0

Answer:

options A and C

Explanation:

Since, the spheres are of same size and rotational speed of the sphere are not dependent on their masses. So, both the sphere will reach the bottom of the at the same time with the same speed. But their kinetic energies are different.

So, options A and C are correct.

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mr Goodwill [35]

Answer:

True

Explanation:

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2 years ago
A box is pulled 6 meters across the ground at a constant velocity by a horizontally applied force of 50 newtons. At the same tim
Vikentia [17]

Answer:

(a) Friction force = 50 N

(b) Work done by friction = 300 j

(c) Net work done = 0 j

Explanation:

We have given that the box is pulled by 6 meter so d = 6 m

Force applied on the box F = 60 N

We have have given that velocity is constant so acceleration will be zero

So to applied force will be utilized in balancing the friction force

So friction force F_{friction}=50N

Work done by friction force W_{friction}=F_{friction}\times d=50\times 6=300j

Work done by applied force W=F\times d=50\times 6=300j

So net work done = 300-300 = 0 j

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3 years ago
Which change in an object would increase the force needed to move the object​
creativ13 [48]

Answer:

force is the answer because force is pushing the item

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Klio2033 [76]

Hello this is to other people looking for the answer. Everyone else is wrong. I just took the quiz on e2020. The answer actually Comparative. Your welcome. Have a nice day.

8 0
3 years ago
A rocket travels 1.3 km in 62 ms. What is its average speed in m⋅s−1? Do not give your answer in scientific notation. The answer
hjlf

Answer:

Average speed = 0.35 m/s

Explanation:

Given the following data;

Distance = 1.3 Km

Time = 62 minutes

To find the average speed in m/s;

First of all, we would convert the quantities to their standard unit (S.I) of measurement;

Conversion:

1.3 kilometres to meters = 1.3 * 1000 = 1300 meters

For time;

1 minute = 60 seconds

62 minutes = X

Cross-multiplying, we have;

X = 62 * 60

X = 3720 seconds

Now, we can calculate the average speed in m/s using the formula;

Speed = \frac {distance}{time}

Speed = \frac {1300}{3720}

Average speed = 0.35 m/s

7 0
3 years ago
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