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shusha [124]
3 years ago
14

Two uniform solid spheres of the same size, but different mass, are released from rest simultaneously at the same height on a hi

ll and roll to the bottom without slipping. Part A Which of the following statements about these spheres are true?
A. Both spheres reach the bottom at the same time.
B. The heavier sphere reaches the bottom ahead of the lighter one.
C. Both spheres arrive at the bottom with the same forward speed.
D. Both spheres arrive at the bottom with the same total kinetic energy.
Physics
1 answer:
SpyIntel [72]3 years ago
4 0

Answer:

options A and C

Explanation:

Since, the spheres are of same size and rotational speed of the sphere are not dependent on their masses. So, both the sphere will reach the bottom of the at the same time with the same speed. But their kinetic energies are different.

So, options A and C are correct.

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To drive a typical car at 40 mph on a level road for onehour requires about 3.2 × 107 J ofenergy. Suppose one tried to store thi
Ainat [17]

Answer:

\omega=943\ rad/s

Explanation:

Given that,

Speed of the car, v = 40 mph

Energy required, E=3.2\times 10^7 J

Radius of the flywheel, r = 0.6 m

Mass of flywheel, m = 400 kg

The kinetic energy of the disk is given by :

E_k=\dfrac{1}{2}I\omega^2

I is the moment of inertia of the disk, I=\dfrac{mr^2}{2}

\omega^2=\dfrac{2E_k}{I}

\omega^2=\dfrac{2E_k}{\dfrac{mr^2}{2}}

\omega^2=\dfrac{2\times 3.2\times 10^7}{\dfrac{400\times (0.6)^2}{2}}

\omega=942.80\ rad/s

or

\omega=943\ rad/s

So, the angular speed of the disk is 943 rad/s. Hence, this is the required solution.

8 0
4 years ago
The Kinetic energy, K, of an object with mass m moving with velocity v can be found using the formula - E_{\text{k}}={\tfrac {1}
tester [92]

Answer:

The ratio of kinetic energies of 5 kg object to 20 kg object is 1:1.

Explanation:

Kinetic energy is defined as energy possessed by an object due to its motion.It is calculated by:

K.E=\frac{1}{2}mv^2

Kinetic energy of the 5 kg object.

Mass of object,m = 5 kg

Velocity of an object = v

K.E=\frac{1}{2}mv^2=\frac{1}{2}\times 5kg\times v^2

Kinetic energy of the 20 kg object.

Mass of object,m' = 20 kg

Velocity of an object = v'

K.E=\frac{1}{2}mv^2=\frac{1}{2}\times 20kg\times v'^2

The ratio of the kinetic energy of the 5 kilogram object to the kinetic energy of the 20-kilogram object:

\frac{K.E}{K.E'}=\frac{\frac{1}{2}\times 5kg\times v^2}{\frac{1}{2}\times 20kg\times v'^2}

Given that, v = 2v'

\frac{K.E}{K.E'}=\frac{1}{1}

The ratio of kinetic energies of 5 kg object to 20 kg object is 1:1.

3 0
3 years ago
With the switch open, roughly what must be the resistance of the resistor on the right for the current out of the battery to be
jeyben [28]

Question:

Assumptions

Voltage of battery = 24 V

Resistance on the right,20Ω parallel to 10 Ω resistor

Answer:

For the current out of the battery to be the same as when the switch was opened with the switch closed, the resistance on the resistor on the right must be approximately 20/3 Ω

Explanation:

We note that the switch in the assumption is on the same line as the 20 Ω resistor.

With a voltage of 24 V, and the switch closed, we have;

Total resistance =  \frac{1}{\frac{1}{10} +\frac{1}{20} } = \frac{20}{3} \Omega

Current out of voltage, I  = Voltage/(total resistance)

= 24 ÷ 20/3 = 24 × 3/20 = 18/5 A

Therefore, with the switch opened, we get

Resistance on the right = Initial total resistance =  \frac{20}{3} \Omega

Therefore, with the switch opened, the resistance on the resistor on the right must be approximately equal to the resultant resistance of the two resistances in parallel.

6 0
3 years ago
A mover slides a refrigerator weighing 650 N at a constant velocity across the floor a distance of 8.1 m. The force of friction
boyakko [2]

Given :

A mover slides a refrigerator weighing 650 N at a constant velocity across the floor a distance of 8.1 m.

The force of friction between the refrigerator and the floor is 230 N.

To Find :

How much work has been performed by the mover on the refrigerator.

Solution :

Since, refrigerator is moving with constant velocity.

So, force applied by the mover is also 230 N ( equal to force of friction ).

Now, work done in order to move the refrigerator is  :

W = Force\times distance\\\\W = 230 \times 8.1\ N\ m\\\\W = 1863\ N\ m

Hence, this is the required solution.

5 0
3 years ago
What is quantitative?
7nadin3 [17]
<span>To relate or measure the by the quantity of something, not against the quantity</span>
5 0
4 years ago
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