An electric radiator consumes 1500 W
1 answer:
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Answer:
E₀ = 5.97 10⁸ N / C
Explanation:
Coulomb's law in a material medium is written
ε is the electrical permittivity of the material
Electric field and force are related
F = q E
in dielectric materials such as mica there is an electric field inside the material that decreases the external field
E = E₀ /ε
where ε is the electrical permittivity of the material; in general it is tabulated in the form
we substitute
F = q E₀ / \epsilon_{r} \epsilon_{o}
for the case of mica it is equal to er = 5.4 and suppose a test charge equal to the charge of the electron
we calculate
E₀ = 2 5.4 8.85 10⁻¹² / 1.6 10⁻¹⁹
E₀ = 59.74 10⁷
E₀ = 5.97 10⁸ N / C