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taurus [48]
3 years ago
11

Olivia bought new gym shoes to play volleyball because she kept slipping when she ran in her old shoes .how will the new soles h

elp solve the problem
Physics
2 answers:
konstantin123 [22]3 years ago
4 0

Answer:

The correct answer is by adding surface roughness to increase friction.

Explanation:

Scrat [10]3 years ago
3 0
By the grip on the bottom
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A pendulum completes 2 oscillation in 5s.
Otrada [13]

Answer:

<h2>a) 2.5 s</h2><h2>b) 1.55 m</h2><h2 />

Explanation:

<h3>Given :-</h3><h2>Completes 2 oscillation in 5s.</h2><h2>A) Time period = ?</h2><h2 /><h2>t \:  = \frac{total \: time \: }{total \: no \: of \: oscillation}</h2><h2 /><h2>\frac{5}{2}  = 2.5s</h2>

<em>Thus 1 oscillation is completed in 2.5 </em><em>s.</em>

<h2>B) If g = 9.8 ms−², find its length.</h2><h2>t \:  = 2\pi  \frac{ \sqrt{l} }{g }</h2><h3>= 2.5s </h3><h3>2\pi \frac{ \sqrt{l} }{g}</h3><h3>Length = ? </h3><h2>\frac{ {t}^{2} }{4\pi {}^{2} }  \times g</h2><h3 /><h3>\frac{2.5}{ {4}^{2} }  \times 9.8 = 1.55m</h3>

Thus the length of g = 9.8 ms −² = 1.55m

<h2>Hope it helps u.......</h2><h2>STAY SAFE, STAY HEALTHY AND BLESSED .</h2><h2> HAVE A MARVELOUS DAY AHEAD !</h2><h2>THANK YOU !</h2>
6 0
2 years ago
2. The amount of charge and the distance from the charge determine the...
cricket20 [7]

Answer:

the answer is c Strength of the electric field

Explanation:

it is that bcause

7 0
3 years ago
Read 2 more answers
A car is stopped for a traffic signal. When the light turns green, the car accelerates, increasing its speed from zero to 5.27 m
jeyben [28]

Answer:

See explanation

Explanation:

From Newton's law; the rate of change of momentum is proportional to the impressed force. Hence;

F.t = mv- mu

F= force

t= time

m= mass

V= final velocity

u = initial velocity

since u = 0, mv= 0

F= MV/t

F= 69.8 × 5.27/0.833

F= 442 N

Impulse = Ft= 442 × 0.833= 368 Ns

5 0
3 years ago
A small sphere of radius R is arranged to pulsate so that its radius varies in simple harmonic motion between a minimum of R−x a
Colt1911 [192]

Answer:

The intensity of sound wave at the surface of the sphere I =   \frac{ 2\pi^{2}R^{2} f^{2}\sqrt{\rho B}(\triangle R)^{2}}{ d^{2} }

Explanation:

B = Bulk modulus

Intensity, I = \frac{P_{max} ^{2} }{2\sqrt{\rho B} }

The amplitude of oscillation of the sphere is given by:

P_{max} = BkA\\k = \frac{2\pi }{\lambda} \\

A = \triangle R\\

Substitute v and A into Pmax

P_{max} = (2\pi f)\sqrt{\rho B} \triangle R\\ P_{max} ^{2} = 4\pi^{2} *f^{2} \rho B (\triangle R)^{2}

I = \frac{ 4\pi^{2} f^{2} \rho B (\triangle R)^{2}}{2\sqrt{\rho B} }

P_{total} = 4\pi R^{2} I

P_{total} =4\pi R^{2}  \frac{ 2\pi^{2} f^{2} \rho B (\triangle R)^{2}}{\sqrt{\rho B} }

The intensity of the sound wave at a distance  is given by:

I = \frac{P_{total} }{4\pi d^{2} }

I = 4\pi R^{2}  \frac{ 2\pi^{2} f^{2} \rho B (\triangle R)^{2}}{\sqrt{\rho B} } * \frac{1}{4\pi d^{2} } \\I =   \frac{ 2\pi^{2}R^{2} f^{2}\sqrt{\rho B}(\triangle R)^{2}}{ d^{2} }

5 0
3 years ago
Thế nào là gương cầu lồi
ale4655 [162]

Answer:

I know I am a very good answerable teacher but I can't answer this question I don't know what

7 0
2 years ago
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