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Anastaziya [24]

3 years ago

7

An electron with a charge e and mass m is accelerated from rest for a time T by a uniform electric field that exerts a force F o

n the electron.What is the magnitude of the electric field?

1 answer:

Basile [38]3 years ago

5 0

Answer:

$E =\frac{F}{e}$

Explanation:

charge of the electron = e

mass of the electron = m

Force due to electric field = F

initial velocity = 0

time taken = T

Electric field is the region around a particle which is charge where in a force is exerted on another particle which is charged.

Force on electron due to presence of uniform electric field (E):

F = e E

⇒ $E =\frac{F}{e}$

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ch4aika [34]

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4 0

3 years ago

A telephone line has a signal-to-noise ratio of 1000 and a bandwidth of 4 KHz. What is the maximum data rate supported by this l

ivolga24 [154]

Answer:

The maximum data rate supported by this line is 39900 bps

Explanation:

The maximum data rate supported by this line can be obtained using the formula below

c = W*log2(S/N+1)

where;

c is the maximum data rate supported by the line

W is the bandwidth = 4kHz

S/N+1 is the signal to noise ratio = 1001

c = 4*log2(1001)

c = 39868.9 ≅ 39900 bps

Therefore, the maximum data rate supported by this line is 39900 bps

5 0

3 years ago

A homeowner uses a snowblower to clear his driveway. knowing that the snow is discharged at an average angle of 40° with the hor

Nesterboy [21]

given that snow is projected at an angle of 40 degree

It range is given as a = 19 ft

$a = 19 * 0.3048 = 5.8 m$

now we can use the formula of horizontal range

$R = \frac{v_o^2 sin2\theta}{g}$

$5.8 =\frac{ v_o^2 sin(2*40)}{9.8}$

$5.8 = \frac{v_o^2 * sin80}{9.8}$

$v_o^2 = 57.7$

$v_o = 7.6 m/s$

<u>so its initial speed must be 7.6 m/s</u>

8 0

3 years ago

The coefficient of linear expansion of ordinary glass is three times that of Pyrex glass. An ordinary glass rod and a Pyrex glas

DochEvi [55]

Answer:

b. 3 times

Explanation:

Lets take

Coefficient for ordinary glass = α₁

Coefficient for pyrex glass = α₂

Given that α₁ = 3 α₂

Initial length of both glasses are equal = L

Change in the temperature is also same .= ΔT

We know that change in the length given as

ΔL = L α ΔT

Therefore

$\dfrac{\Delta L_1}{\Delta L_2}=\dfrac{L\alpha_1\Delta T}{L\alpha_2\Delta T}$

$\dfrac{\Delta L_1}{\Delta L_2}=\dfrac{3\alpha_2}{\alpha_2}$

ΔL₁ = 3ΔL₂

Therefore change in the length of original glass is three time of pyrex glass.

b. 3 times

6 0

3 years ago

6.7.1 Current and Current Density A sphere of radius 10 mm that carries a charge of 8 nC =8x 10°C is whirled in a circle at the

aev [14]

Answer:

Part a)

Rate of charge flow is known as electric current

Part b)

Average current flow is

$i = 4\times 10^{-7} A$

Part c)

As we know that current density is current per unit area

$j = 1.27 \times 10^{-3} A/m^2$

Explanation:

As we know that angular frequency of rotation is

$\omega = 100\pi rad/s$

now by basic definition of electric current

Part a)

Rate of charge flow is known as electric current

$i = \frac{dq}{dt}$

so here we have

$i = \frac{Q}{T}$

$i = Qf$

Part b)

here we know that

$\omega = 2\pi f$

$100\pi = 2\pi f$

$f = 50 Hz$

now we have

$i = (8\times 10^{-9})(50)$

$i = 4\times 10^{-7} A$

Part c)

As we know that current density is current per unit area

So we have

$j = \frac{i}{A}$

$j = \frac{4\times 10^{-7}}{\pi(10\times 10^{-3})^2}$

$j = 1.27 \times 10^{-3} A/m^2$

6 0

3 years ago