Question

An electron with a charge e and mass m is accelerated from rest for a time T by a uniform electric field that exerts a force F on the electron.What is the magnitude of the electric field?

Answer 1

Answer:

$E =\frac{F}{e}$

Explanation:

charge of the electron = e

mass of the electron = m

Force due to electric field = F

initial velocity = 0

time taken = T

Electric field is the region around a particle which is charge where in a force is exerted on another particle which is charged.

Force on electron due to presence of uniform electric field (E):

F = e E

⇒$E =\frac{F}{e}$