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fgiga [73]
3 years ago
9

Bedrock that is closer to oceanic ridges is younger in age than bedrock that is farther away. What can best be concluded from th

is
information
Physics
1 answer:
Art [367]3 years ago
7 0
The shape of Earth's lithosphere is continually changing. Bedrock that is closer to oceanic ridges is younger in age than bedrock that is farther away. What can best be concluded from this information? It can cause pollution of water in lakes and rivers
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What's the concept of mass ?
Marat540 [252]
Masa is a concept that identifies that magnitude of a physical nature that allows indicating the amount of matter in a body. Within the International System , its unit is the kilogram ( kg . ) 
6 0
2 years ago
What type of Circuit do they use in a home? WHY ? (Simple circuit / Parallel circuit / Series circuit) helpp
Vikentia [17]

Answer:

Parallel

Explanation:

Most standard 120-volt household circuits in your home are (or should be) parallel circuits. Outlets, switches, and light fixtures are wired in such a way that the hot and neutral wires maintain a continuous circuit pathway independent from the individual devices that draw their power from the circuit.

Hope that helps :)

7 0
2 years ago
A hiker walks 20.51 m at 33.16 degrees. What is the Y component of his displacement?
Serhud [2]

Answer:

<em>The y component of his displacement is 11.22 meters</em>

Explanation:

<u>Components of the displacement</u>

The displacement is a vector because it has a magnitude and a direction. Let's suppose a displacement has a magnitude r and a direction θ, measured with respect to the positive x-direction. The horizontal component of the displacement is calculated by:

x=r\cos\theta

The vertical component is calculated by:

y=r\sin\theta

The hiker has a displacement with magnitude r = 20.51 m at an angle of 33.16 degrees. Substituting in the above equation:

y=20.51\sin(33.16^\circ)

y=11.22\ m

The y component of his displacement is 11.22 meters

7 0
3 years ago
Suppose the coefficient of static friction between a quarter and the back wall of a rocket car is 0.383. At what minimum rate wo
djverab [1.8K]

Answer:

25.59 m/s²

Explanation:

Using the formula for  the force of static friction:

f_s = \mu_s N --- (1)

where;

f_s = static friction force

\mu_s = coefficient of static friction

N = normal force

Also, recall that:

F = mass × acceleration

Similarly, N = mg

here, due to min. acceleration of the car;

N = ma_{min}

From equation (1)

f_s = \mu_s ma_{min}

However, there is a need to balance the frictional force by using the force due to the car's acceleration between the quarter and the wall of the rocket.

Thus,

F = f_s

mg = \mu_s ma_{min}

a_{min} = \dfrac{mg }{ \mu_s m}

a_{min} = \dfrac{g }{ \mu_s }

where;

\mu_s = 0.383 and g = 9.8 m/s²

a_{min} = \dfrac{9.8 \ m/s^2 }{0.383 }

\mathbf{a_{min}= 25.59 \ m/s^2}

3 0
2 years ago
A man wishes to pull a crate 15m across a rough floor by exerting a force of 100 N. The
Darina [25.2K]

Answer:

option (E) is correct.

Explanation:

Work done is defined as the product of force and the distance in the direction of force.

force, f = 100 N

Coefficient of friction, = 0.25

distance = 15 m

So, net force F = f - friction force

F = 100 - 0.25 x m g

Work = (100 - 0.25 mg) x d cosθ

For minimum work, the angle should be maximum.

So, the value of θ is 76°.

thus, option (E) is correct.

3 0
3 years ago
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