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Mashutka [201]
2 years ago
7

A spring has a spring constant of 450 N/m. How much must this spring be stretched to store 49 J of potential energy?

Physics
1 answer:
Mazyrski [523]2 years ago
6 0

Answer:

x = 0.47 m

Explanation:

PS = ½kx²

x = √(2PS/k) = √(2(49)/450)) = 0.466666...

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a)

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b)

When T= 35 N

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