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3 years ago

A spring has a spring constant of 450 N/m. How much must this spring be stretched to store 49 J of potential energy?

Physics

1 answer:

Mazyrski [523]3 years ago

6 0

Answer:

x = 0.47 m

Explanation:

PS = ½kx²

x = √(2PS/k) = √(2(49)/450)) = 0.466666...

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