The height of the kite above the ground is 58.68 ft
Let x be the height of the kite above Chee's hand.
The height of the kite above Chee's hand, the string and the horizontal distance between Chee and the kite form a right angled triangle with hypotenuse side, the length of the string and opposite side the height of the kite above Chee's hand.
Since we have the angle of elevation from her hand to the kite is 29°, and the length of the string is 100 ft.
From trigonometric ratios, we have
tan29° = x/100
So, x = 100tan29°
x = 100 × 0.5543
x = 55.43 ft.
Since Chee's hand is y = 3.25 ft above the ground, the height of the kite above the ground, L = x + y
= 55.43 ft + 3.25 ft
= 58.68 ft to the nearest hundredth of a foot
So, the height of the kite above the ground is 58.68 ft
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Answer:
Answer: 1/81
First you simplify it to 3^-4
Then express it with a positive exponent
which goes to 1/3^4
Then evaluate it to 1/81
22x12x5 and you will get the answer
Answer:
StartFraction x over 7.5 EndFraction = StartFraction 12 over 1 EndFraction
Step-by-step explanation:
Here, in this question, given that Rosa earns $12 in an hour, she earns x dollars in 7.5 hours. So we are interested in finding the value of x.
Let’s write this in terms of proportion;
$12 = 1 hour
$x = 7.5 hours
$12 * 7.5 hours = $x * 1 hour
So this can be rewritten as;
$x/7.5 = $12/1 hour
