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Teresa went out to lunch with her sister. The bill was $32.20. She had a

Norma-Jean [14]

Answer:

$31

Step-by-step explanation:

First, to find how much the total was after we coupon we have to multiply 32.20 by 0.10. when we do that we get 3.22. Since the coupon was a discount we subtract 3.22 from 32.20 to get 28.98. We then multiply 28.98 by 0,07 to find out how much the 7% tax is. When you do that you get 2.0286. Add that to 28.98 since the tax add to the price. When you do that your answer round up to $31.

5 0

3 years ago

Read 2 more answers

Why is the square root of 7 irrational

BigorU [14]

Answer:

dude you should know this one it's obviously not see and if it's a perfect square root then it wouldn't be irrational the answer B

3 0

3 years ago

Quadrilateral ABCD with vertices A(0, 6), B(-3, -6), C(-9, -6), and D(-12, -3): a) dilation with scale factor of 1/3 centered at

Oksanka [162]

a) The points of the new quadrillateral are $A'(x,y) = (0, 2)$ , $B'(x,y) = (-1, -2)$ , $C'(x,y) = \left(-3,-2\right)$ and $D'(x,y) = (-4, -1)$ , respectively.

b) The points of the new quadrillateral are $A'(x,y) = (-5, 5)$ , $B'(x,y) = (-8,-7)$ , $C'(x,y) = (-13, -7)$ and $D'(x,y) = (-17, -4)$ , respectively.

<h3>How to perform transformations with points</h3>

a) A dillation centered at the origin is defined by following operation:

$P'(x,y) = k\cdot P(x,y)$ (1)

Where:

$P(x,y)$ - Original point
$P'(x,y)$ - Dilated point.

If we know that $k = \frac{1}{3}$ , $A(x,y) = (0,6)$ , $B(x,y) = (-3,-6)$ , $C(x,y) = (-9, -6)$ and $D(x,y) = (-12, -3)$ , then the new points of the quadrilateral are:

$A'(x,y) = \frac{1}{3}\cdot (0,6)$

$A'(x,y) = (0, 2)$

$B'(x,y) = \frac{1}{3} \cdot (-3,-6)$

$B'(x,y) = (-1, -2)$

$C'(x,y) = \frac{1}{3}\cdot (-9,-6)$

$C'(x,y) = \left(-3,-2\right)$

$D'(x,y) = \frac{1}{3}\cdot (-12,-3)$

$D'(x,y) = (-4, -1)$

The points of the new quadrillateral are $A'(x,y) = (0, 2)$ , $B'(x,y) = (-1, -2)$ , $C'(x,y) = \left(-3,-2\right)$ and $D'(x,y) = (-4, -1)$ , respectively. $\blacksquare$

b) A translation along a vector is defined by following operation:

$P'(x,y) = P(x,y) +T(x,y)$ (2)

Where $T(x,y)$ is the transformation vector.

If we know that $T(x,y) = (-5,-1)$ , $A(x,y) = (0,6)$ , $B(x,y) = (-3,-6)$ , $C(x,y) = (-9, -6)$ and $D(x,y) = (-12, -3)$ ,

$A'(x,y) = (0,6) + (-5, -1)$

$A'(x,y) = (-5, 5)$

$B'(x,y) = (-3, -6) + (-5, -1)$

$B'(x,y) = (-8,-7)$

$C'(x,y) = (-9, -6) + (-5, -1)$

$C'(x,y) = (-13, -7)$

$D'(x,y) = (-12,-3)+(-5,-1)$

$D'(x,y) = (-17, -4)$

The points of the new quadrillateral are $A'(x,y) = (-5, 5)$ , $B'(x,y) = (-8,-7)$ , $C'(x,y) = (-13, -7)$ and $D'(x,y) = (-17, -4)$ , respectively. $\blacksquare$

To learn more on transformation rules, we kindly invite to check this verified question: brainly.com/question/4801277

7 0

3 years ago

The count of bacteria in a certain experiment was increasing at a rate of 2.5% per hour. if the experiment started with 1600. fi

krok68 [10]

The bacteria at the end of 22 hours is 2,480

5 0

3 years ago

HELP i will give brainliest all questions ;(

Rama09 [41]

Answer:

1. The theoretical probability of rolling an even number and flipping heads is 25%.

2. The experimental probability of rolling a 1 and flipping tails is 15%.

3. The experimental probability of flipping heads is 40%.

4. I think around 7%.

5. I would expect to roll 3 and land on heads 8 times.

Step-by-step explanation:

I am not sure about number 4.

Have a nice day!

Ask me if you need my work. :-)

8 0

3 years ago