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3 years ago

HELPPPPPPPPPPPPPPPPPPPPPPPPPPPPP

Mathematics

1 answer:

andrew11 [14]3 years ago

3 0

Ummm not to freak you out but what’s that in the background?

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If the number of bacteria in a colony doubles every 8 hours and there is currently a population of 9,315 bacteria, what will the

Liono4ka [1.6K]

It is given that the bacteria in a colony doubles every 8 hours.

To find the population of bacteria 24 hours from now, we need to find the population of bacteria after every 8 hours.

The present population of the bacteria is 9315.

After 8 hours, the bacteria becomes double. So, the number of bacteria becomes 9315 x 2 = 18630.

Again after 8 hours, the bacteria becomes 18630 x 2 = 37260.

Again after 8 hours, the bacteria becomes 37260 x 2 = 74520.

Thus, after 24 hours from now, the population of the bacteria is 74520.

8 0

1 year ago

30000 at 8% per year for 10 months equals to

motikmotik

Answer:

2000

Step-by-step explanation:

S.I=P×rate / 100×time

30000×8 / 100×5/6

=2000

3 0

3 years ago

Simplify. −38+(1+22)2

Hitman42 [59]

It would be 3 over 5

4 0

3 years ago

what is the quotient 5-x/x^2 3x-4 divided by x^2-2x-15/x^2 5x 4 in simplifed form state any restrictions on the varible

zheka24 [161]

The quotient when $\frac{5-x}{x^2+3x-4} /\frac{x^2-2x - 15}{x^2+5x+4}$ in simplified form is $\frac{-(x+1)}{(x-1)(x+3)}$

<h3>What is an equation?</h3>

An equation is an expression that shows the relationship between two or more numbers and variables.

Given that equation:

$\frac{5-x}{x^2+3x-4} /\frac{x^2-2x - 15}{x^2+5x+4}$

$=\frac{5-x}{(x+4)(x-1)} /\frac{(x-5)(x+3)}{(x+4)(x+1)} \\\\=\frac{5-x}{(x+4)(x-1)} * \frac{(x+4)(x+1)}{(x-5)(x+3)}\\\\\frac{-(x-5)}{(x+4)(x-1)} * \frac{(x+4)(x+1)}{(x-5)(x+3)}\\\\=\frac{-(x+1)}{(x-1)(x+3)}$

The quotient when $\frac{5-x}{x^2+3x-4} /\frac{x^2-2x - 15}{x^2+5x+4}$ in simplified form is $\frac{-(x+1)}{(x-1)(x+3)}$

Find out more on equation at: brainly.com/question/2972832

#SPJ1

8 0

2 years ago

What are the ordered pairs of the

OlgaM077 [116]

Answer:

The two points solutions to the system of equations are: (2, 3) and (-1,6)

Step-by-step explanation:

These system of equations consists of a parabola and a line. We need to find the points at which they intersect:

$x^2-2x+3=-x+5\\x^2-2x+x+3-5=0\\x^2-x-2=0\\(x-2)(x+1)=0$

Since we were able to factor out the quadratic expression, we can say that the x-values solution of the system are:

x = 2 and x = -1

Now, the associated y values we can get using either of the original equations for the system. We pick to use the linear equation for example:

when x = 2 then $y=-(2)+5=3$

when x= -1 then $y=-(-1)+5=6$

Then the two points solutions to the system of equations are: (2, 3) and (-1,6)

6 0

3 years ago