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Elanso [62]
3 years ago
10

A rolling ball has an initial velocity of 5 meters per second. 30 seconds later, its velocity it 2 meters per second. What is th

e acceleration of the ball?
-1
-0.2
5
Physics
2 answers:
sergeinik [125]3 years ago
5 0
The answer is -0.2 hope this helps. :)
fenix001 [56]3 years ago
3 0

Answer:

dude ur answers are poopy stank their wrong im not rude tho the answer is -0.1

Explanation:

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A car travels at a steady 40.0 m/s around a horizontal curve of radius 200 m. What is the minimumcoefficient of static friction
zhenek [66]

Answer:

c. 0.816

Explanation:

Let the mass of car be 'm' and coefficient of static friction be 'μ'.

Given:

Speed of the car (v) = 40.0 m/s

Radius of the curve (R) = 200 m

As the car is making a circular turn, the force acting on it is centripetal force which is given as:

Centripetal force is, F_c=\frac{mv^2}{R}

The frictional force is given as:

Friction = Normal force × Coefficient of static friction

f=\mu N

As there is no vertical motion, therefore, N=mg. So,

f=\mu mg

Now, the centripetal force is provided by the frictional force. Therefore,

Frictional force = Centripetal force

f=F_c\\\\\mu mg=\frac{mv^2}{R}\\\\\mu=\frac{v^2}{Rg}

Plug in the given values and solve for 'μ'. This gives,

\mu = \frac{(40\ m/s)^2}{200\ m\times 9.8\ m/s^2}\\\\\mu=\frac{1600\ m^2/s^2}{1960\ m^2/s^2}\\\\\mu=0.816

Therefore, option (c) is correct.

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4 years ago
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Just divide the both, you will get the answer!

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