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3 years ago

Using the picture below, what is the displacement of the triangle?

Physics

1 answer:

zavuch27 [327]3 years ago

7 0

Answer:

i think it is 40 kilometers in the positive direction... if not im sorry

Explanation:

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Julia and her musician friends were competing in the school talent show. Julia wanted her band to win the "most talented" award,

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No, because she is hoping people vote for her.

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3 years ago

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The Event Horizon Telescope needs a 22 micro-arcsecond resolution to view the event horizon regions around black holes. If the a

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Answer:

14869817.395 m

Explanation:

$\theta$ =22 microarcsecond

λ = Wavelength = 1.3 mm

Converting to radians we get

$22\times 10^{-6}\frac{\pi}{180\times 3600}\ radians$

From Rayleigh Criterion

$\theta=1.22\frac{\lambda}{D}\\\Rightarrow D=1.22\frac{\lambda}{\theta}\\\Rightarrow D=1.22\frac{1.3\times 10^{-3}}{22\times 10^{-6}\frac{\pi}{180\times 3600}}\\\Rightarrow D=14869817.395\ m$

Diameter of the effective primary objective is 14869817.395 m

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3 years ago

What device is like the reverse of an electric motor?

nignag [31]

Answer:

a. Generator

Explanation:

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3 years ago

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Satellite A orbits a planet at a distance d from the planet’s center with a centripetal acceleration a0. A second identical sate

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To solve this problem it is necessary to use the concepts related to the Gravitational Force and Newton's Second Law, as far as we know:

$F_g = \frac{GMm}{r^2}$

Where,

G = Gravitational constant

M = Mass of earth (in this case)

m = mass of satellite

r = radius

In the other hand we have the second's newton law:

$F = ma$

Where,

m = mass

a = acceleration

Equation both equations we have,

$ma = \frac{GMm}{r^2}$

For the problem we have that,

Satellite A:

$ma_A = \frac{GMm}{r^2}$

Satellite B:

$ma_B = \frac{GMm}{(2r)^2}$

The ratio between the two satellites would be,

$\frac{ma_A}{ma_B}= \frac{\frac{GMm}{r^2}}{\frac{GMm}{(2r)^2}}$

Solving for a_B,

$a_B = \frac{a_A}{4}$

Therefore the centripetal acceleration of $A_B$ is a quarter of $a_A$

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3 years ago

During a total lunar eclipse, the Earth, Sun, and Moon are arranged in a line, and the Moon is completely dark.

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Lunar eclipses are governed by the same principle as solar eclipses: In this case however, the Earth 'slides itself' between the Moon and the Sun.

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4 years ago

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