Answer:
The vapor pressure is 748.77 torr
Explanation:
Using Clausius-Clapeyron equation:
where;
T₁ is the initial temperature = 85.0°F = 302.5 K
T₂ is the final temperature = 100 °C = 373 K
P₂ is the final pressure = 760 torr
P₁ is the initial pressure = vapor pressure = ?
R is gas constant = 8.314 J/K.mol
ΔHvap is the heat of vaporization of water = 40.7 kJ/mol
4.895(0.00331 - 0.00268) = 0.01489
= 1.015
P₁ = (760 torr)/(1.015) = 748.77 torr
Therefore, the vapor pressure is 748.77 torr
When energetic UV rays dissociates molecules of oxygen into seperate atoms. But when they collide into each other it forms OZONE.
Answer:
The answer is
D. 1230j
Explanation:
When a bullet is shot out of a gun the person firing experiences a backward impact, which is the recoil force, while the force propelling the bullet out of the gun is the propulsive force
given data
Mass of gun M=10kg
Mass of bullet m=20g----kg=20/1000 =0.02kg
Propulsive speed of bullet = 350m/s
Hence the moment of the bullet will be equal and opposite to that of the gun
mv=MV
where V is the recoil velocity which we are solving for
V=mv/M
V=0.02*350/10
V=7/10
V=0.7m/s
The energy contained in the bullet can be gotten using
KE=1/2m(v-V)²
KE=1/2*0.02(350-0.7)²
KE=1/2*0.02(349.3)²
KE=1/2*0.02*122010.49
KE=1/2*2440.20
KE=1220.1J
roughly the energy is 1230J
Explanation:
The given data is as follows.
mass = 227.8 kg, volume = 0.1189
It is known that formula for volume of a sphere is and density is as follows.
Density = ........ (1)
=
= 1915.895
Hence, putting the given values into equation (1) as follows.
Density =
1915.895 =
= 227.8
r = 0.305
Thus, we can conclude that radius of the sphere is 0.305 .
I am guessing the answer to your question, is calories.