1. mol ratio of Al(NO₃)₃ : Na₂CO₃ = 2 : 3
2. Na₂CO₃ as a limiting reactant
<h3>Further explanation</h3>
Given
Reaction
2 Al(NO₃)₃ + 3 Na₂CO₃ → Al₂(CO₃)₃ + 6 NaNO₃
Required
mol ratio
Limiting reactant
Solution
The reaction coefficient in the chemical equation shows the mole ratio of the components of the compound involved in the reaction (reactants and products)
1. From the equation mol ratio of Al(NO₃)₃ : Na₂CO₃ = 2 : 3
2. mol : coefficient of Al(NO₃)₃ : Na₂CO₃ = 2 mole/2 : 2 mole/3 = 1 : 0.67
Na₂CO₃ as a limiting reactant (smaller)
Answer:
false?
Explanation:
The octet rule refers to the tendency of atoms to prefer to have eight electrons in the valence shell. When atoms have fewer than eight electrons, they tend to react and form more stable compounds
Answer:
c. ΔH° is positive and ΔS° is positive.
Explanation:
Hello,
In this case, as the Gibbs free energy for a reaction is defined in terms of the change in the enthalpy and entropy as shown below:
Thus, as the reaction becomes spontaneous (ΔG°<0) at temperatures above 1100K (high temperatures), it necessary that c. ΔH° is positive and ΔS° is positive as the entropy will drive the spontaneousness as it becomes smaller than TΔS°.
Best regards.
Answer: 2.74 litres
Explanation:
Given that,
Original pressure of balloon (P1) = 100.0 kPa
Original volume of balloon (V1) = 2.29 litres
New pressure of balloon (P2) = 83.5 kPa
New volume of balloon (V2) = ?
Since pressure and volume are given while temperature is held constant, apply the formula for Boyle's law
P1V1 = P2V2
100 kPa x 2.29 L = 83.5 kPa x V2
229 kPa•L = 83.5 kPa•V2
Divide both sides by 83.5 kPa
229 kPa•L/83.5 kPa = 83.5 kPa•V2/ 83.5 kPa
2.74 L = V2
Thus, the new volume of the balloon is 2.74 litres
Answer:
Answers may vary
Explanation:
Mol is the amount of molecules in something. Mol are similar to donuts, if you have a dozen of something you have 12 of them. If you have a mol of Hydrogen gas you 6.02•10^23 molecules of Hydrogen gas. If you are taking a chemistry class you will probably receive questions involving converting grams to mol and vice versa.
Converting Grams to Mol:
grams of x•(1/molecular mass of x)
note: you can find molecular mass of x by looking at the masses of the elements you need to add up in the periodic table
Converting Mol to Grams:
mol of x•(molecular mass of x)
