Ask question

Ask question

All categories

3 years ago

12

How is the electron configuration of an anion different from that of the corresponding neutral atom?how is the electron configur

ation of an anion different from that of the corresponding neutral atom?

1 answer:

irinina [24]3 years ago

6 0

The electronic configuration of an anion is more than that from that of the corresponding neutral atom.

You might be interested in

1. An atom that has an outer shell that is NOT full is (more likely OR less likely) to be reactive than an atom that has a full

Simora [160]

It would be more likely because it is considered unstable more reactive.

5 0

4 years ago

How many moles of silicon (Si) are in 1.50 x 1023 atoms Si?

erik [133]

Answer:

1534.5

Explanation:

you just multiply i think

8 0

3 years ago

A scientist suggests putting solar panels on homes to supply energy because it is usually sunny there. The amount of sun is BEST

Ne4ueva [31]

Answer:

the answer is a because if u have good wheather the panels will for no matter what

5 0

3 years ago

For Questions 1 through 4 - Consider a solution prepared by combining 45.0 g of BaCl2 with enough water to prepare a 750.0 mL of

astra-53 [7]

<u>Answer:</u> The molality of barium chloride solution is 0.289 m

<u>Explanation:</u>

To calculate the mass of water, we use the equation:

$\text{Density of substance}=\frac{\text{Mass of substance}}{\text{Volume of substance}}$

Density of water = 1 g/mL

Volume of water = 748 mL

Putting values in above equation, we get:

$1g/mL=\frac{\text{Mass of water}}{748mL}\\\\\text{Mass of water}=(1g/mL\times 748mL)=748g$

To calculate the molality of solution, we use the equation:

$\text{Molality}=\frac{m_{solute}\times 1000}{M_{solute}\times W_{solvent}\text{ (in grams)}}$

where,

$m_{solute}$ = Given mass of solute (barium chloride) = 45.0 g

$M_{solute}$ = Molar mass of solute (barium chloride) = 208.23 g/mol

$W_{solvent}$ = Mass of solvent (water) = 748 g

Putting values in above equation, we get:

$\text{Molality of barium chloride solution}=\frac{45\times 1000}{208.23\times 748}\\\\\text{Molality of barium chloride solution}=0.289m$

Hence, the molality of barium chloride solution is 0.289 m

5 0

3 years ago

nasty-shy [4]

Answer:

300g of water because its a larger amount

Explanation:

3 0

3 years ago