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gregori [183]
3 years ago
14

Analysis of an ore of calcium shows that it contains 13.61 g calcium and 21.77 g oxygen in a 46.28-g sample. Calculate the perce

nt composition of this compound.
Chemistry
1 answer:
kondor19780726 [428]3 years ago
5 0

Answer:

29.41% of Calcium and 47.04% of Oxygen

Explanation:

The percent composition of an atom in a molecule is defined as 100 times the ratio between the mass of the atom and the mass of the molecule.

The mass of the molecule of the problem (Ore) is 46.28g. That means the percent composition of Calcium is:

13.61g / 46.28g * 100 = 29.41% of Calcium

And percent composition of Oxygen is:

21.77g / 46.28g * 100 = 47.04% of Oxygen

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Evgesh-ka [11]

Answer:

30 cm³

Explanation:

Step 1: Given data

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Step 2: Calculate the volume occupied by aluminum

The density of aluminum is equal to its mass divided by its volume.

ρ = m/V

V = m/ρ

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Sladkaya [172]

Answer:

see explanation below

Explanation:

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Now, in general terms, the absorbance of a substance can be calculated using the beer's law which is the following:

A = εlc

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