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gregori [183]
3 years ago
14

Analysis of an ore of calcium shows that it contains 13.61 g calcium and 21.77 g oxygen in a 46.28-g sample. Calculate the perce

nt composition of this compound.
Chemistry
1 answer:
kondor19780726 [428]3 years ago
5 0

Answer:

29.41% of Calcium and 47.04% of Oxygen

Explanation:

The percent composition of an atom in a molecule is defined as 100 times the ratio between the mass of the atom and the mass of the molecule.

The mass of the molecule of the problem (Ore) is 46.28g. That means the percent composition of Calcium is:

13.61g / 46.28g * 100 = 29.41% of Calcium

And percent composition of Oxygen is:

21.77g / 46.28g * 100 = 47.04% of Oxygen

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Explanation:

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The last step is assign a value to a letter. I, for example, will say that <em>a is 1, </em>and then find the values for the others letters, thus:

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Fe₂O₃ + 3 CO → 2 Fe + 3 CO₂

I hope it helps!

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