Answer:
80g
Explanation:
mass oxygen present in 1 mole of p4010
16×10=160gm
similarly
for 0.5 moles of p4010 160/2= 80gm
Answer: 2, 13, 8, 10 (sorry if i’m wrong lol)
Explanation:
Answer: I think the answer is C. NaCl and H2O
Explanation: I’m not sure tho
Answer:
D = Mass = 42.6 g
Explanation:
Given data:
Mass of phosphorus react = 33 g
Mass of oxygen needed = ?
Solution:
Chemical equation:
4P + 5O₂ → 2P₂O₅
Number of moles of phosphorus:
Number of moles = mass/molar mass
Number of moles = 33 g/ 30.97 g/mol
Number of moles = 1.065 mol
now we will compare the moles of phosphorus and oxygen.
P : O₂
4 : 5
1.065 : 5/4×1.065 = 1.33mol
Mass of oxygen needed:
Mass = number of moles × molar mass
Mass = 1.33 mol × 32 g/mol
Mass = 42.6 g
Thus, 43.6 g of oxygen needed to react with 33 g of phosphorus.
