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Viefleur [7K]
3 years ago
10

I don't remember how to solve this

Mathematics
1 answer:
EastWind [94]3 years ago
5 0

Answer:

me too i fogort eventhough i did something just like it

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Step-by-step explanation:

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the weight of an object on mars varies directly as the weight of the object on earth a 90 pound object on earth weighs 34 pounds
Mariulka [41]

We have been given that the weight of an object on the mars varies directly as the weight of the object on earth.  

Let y be weight of an object on Mars and x be weight of an object on Earth.

\\&#10;y=kx

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Putting the given values in equation we get

\\&#10;34=k(90)\\&#10;\\&#10;k=\frac{34}{90}=\frac{17}{45}

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\\&#10;y= \frac{17}{45}x

Now we have been given that the weight of an object on Earth is 135 pounds and we have to find the weight of the same object on Mars,

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Putting the given values in our equation we get

\\&#10;y= \frac{17}{45}(135)=\frac{17\cdot 135}{45}=17\cdot 3 = 51

Therefore weight of the object on Mars will be 51 pounds.

                                                                             

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If 5 rubber stamps cost $9.70 what equation would help determine the cost of 11 rubber stamps?
aalyn [17]
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Explanation:

The given quadratic equation is y=3x^{2} +bx-2

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To determine the value of b, let us substitute the coordinates (-2,4) in the given quadratic equation y=3x^{2} +bx-2

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4=3(4)-2b-2

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4=10-2b

Subtracting both sides by 10, we have,

-6=-2b

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b=3

Hence, the value of b is b=3

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