Answer:
Step-by-step explanation:
If Samantha's earnings continue to increase at the same rate, this means that her earning is increasing arithmetically.
If she earned $550 in the first day, we can say the first term is $550
If she earned $750 on the third day, we can say the third term is $750
For us to know by how much her money is increasing, we need to find the common difference d formed by the sequence
550, x , 750
T1 = 550
T2 = x
T3 = 750
Common difference d = T2-T1 = T3-T2
x - 550 = 750 - x = d
Let's calculate the second term first i.e x
Since x - 550 = 750 - x = d
x - 550 = 750 - x
Collect like terms
x+x = 750+550
2x = 1300
x = 1300/2
x = 650
d = T2-T1
d = x - T1
d = 650-550
d = 100
Hence her money keeps increasing by $100 each day
Answer:9 adult tickets and 2 kid tickets
Step-by-step explanation:
The derivative of 1/logx is With the chain rule.
1log(x)=log(x)−1 is ,= -1xlog(x)2 .
The by-product of logₐ x (log x with base a) is 1/(x ln a). Here, the thrilling issue is that we have "ln" withinside the by-product of "log x". Note that "ln" is referred to as the logarithm (or) it's miles a logarithm with base "e".
The by-product of 1/log x is -1/x(log x)^2. Note that 1/logx is the reciprocal of log.
Read more about derivatives;
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Answer:
yes I know what I mean to you can be the next rikage to get out there nationalityand and get a doberman baby driver and the Mather family and the kids will have a great weekend in my room to get to know that they are very good friends or not to see my father did it for the first round and
Answer:
We use Baye's theorem: P(A)P(B|A) = P(B)P(A|B)
with (A) being defective and
(B) marked as defective
we have to find P(B) = P(A).P(B|A) + P(¬A)P(B|¬A). .......eq(2)
Since P(A) = 0.1 and P(B|A)=0.9,
P(¬A) = 1 - P(A) = 1 - 0.1 = 0.9
and
P(B|A¬) = 1 - P(¬B|¬A) = 1 - 0.85 = 0.15
put these values in eq(2)
P(B) = (0.1 × 0.9) + (0.9 × 0.15)
= 0.225 put this in eq(1) and solve for P(B)
P(B) = 0.4
