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MArishka [77]
4 years ago
10

Which changes would cause an increase in the resistance of a wire?

Physics
1 answer:
Fudgin [204]4 years ago
6 0

Answer:

Resistance can increase relative to Temperature, Nature of Material, Length of Conductor or wire.,and Cross-section area.

Explanation:

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Who knows how to do this?
stepladder [879]

I do, and my brother and son-in-law can also solve it.

Note: V1, V2, V3, I1, I2, and I3 are not labeled in the picture, so those can't be solved for.

7 0
3 years ago
Please help! I'd really appreciate it :-)
Alexxx [7]

Answer:

0.31429 Amps

Explanation:

Using the "Ohm's Law" we can look for the current (amps) with a formula of I = V/R

Given:

Resistance (Ohm) = 350

Volts = 110

Solution:

I = 110v/350r

I = 0.31429 amps

6 0
3 years ago
What is the definition of the word amplitude
qwelly [4]

Explanation:

Amplitude, in physics, the maximum displacement or distance moved by a point on a vibrating body or wave measured from its equilibrium position. It is equal to one-half the length of the vibration path. ... Waves are generated by vibrating sources, their amplitude being proportional to the amplitude of the source.

8 0
3 years ago
A light, flexible cable is wrapped around a solid cylinder with mass 3.3 kg and a radius of 0.8 meters. The cylinder rotates on
kari74 [83]

Answer:

9.16rad/s^2

Explanation:

We are given that

Mass,m_1=3.3 kg

Radius,r=0.8 m

m_2=4.9 kg

Height,h=2.9 m

We have to find the angular acceleration of the cylinder.

According to question

4.9g-T=4.9a

Tr=I\alpha

Where

\alpha=\frac{a}{r}

Tr=\frac{1}{2}m_1ra

T=\frac{1}{2}m_1a=\frac{1}{2}(3.3)a

Substitute the value

4.9g-\frac{1}{2}(3.3a)=4.9a

4.9\times 9.8=4.9a+\frac{3.3a}{2}

Where g=9.8 m/s^2

48.02=a(4.9+1.65)=6.55a

a=\frac{48.02}{6.55}=7.33m/s^2

Angular acceleration,\alpha=\frac{a}{r}=\frac{7.33}{0.8}=9.16rad/s^2

7 0
3 years ago
A submarine can detect an approaching enemy submarine using sonar. If a stationary submerged submarine emits a 100kHz tone and r
kotegsom [21]

Answer:

B) 1.5 m/s

Explanation:

The apparent frequency will be enhanced due to Doppler effect

If f be the apparent frequency , F be the real frequency  , V be the velocity of sound and v be the velocity of approaching submarine then f is given by

f = F \frac{V+v}{V-v}\\

\frac{f}{F} =\frac{V+v}{V-v}\\  

\frac{f}{F}-1  =\frac{V+v}{V-v}-1\\

\Delta f = \frac{2vf}{V-v}\\

200=\frac{2\times v\times 100\times 1000}{1482-v}\\  

v=1.48 m/s

7 0
4 years ago
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