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3 years ago

Astronomy question, what keeps supernova explosions from being seen?

Physics

1 answer:

kirill115 [55]3 years ago

4 0

a star that suddenly increases greatly in brightness because of a catastrophic explosion that ejects most of its mass.

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Consider a deer that runs from point A to point B. The distance the deer runs can be greater than the magnitude of its displacem

Serga [27]

Answer:

True

Explanation:

Distance is defined as the length of the actual path traveled by the body.

Displacement is defined as the minimum distance between the two points.

the magnitude of displacement is always less than or equal to the distance traveled by the body.

As a deer runs from A to b , so it means the distance traveled by the deer is either equal to the magnitude of displacement or always greater than the magnitude of displacement of the deer.

Displacement can never be greater than the distance.

Thus, the option is true.

6 0

3 years ago

The electric potential difference of a 150 µF capacitor is measured across the terminals of the capacitor and found to be 5 volt

Lapatulllka [165]

The potential energy stored in a capacitor is given by:
$U= \frac{1}{2}CV^2$
where
C is the capacitance of the capacitor
V is the potential difference across the plates of the capacitor

In our problem,
$C=150 \mu F= 150 \cdot 10^{-6} F$
$V=5 V$
Therefore, the potential energy of the capacitor is
$U= \frac{1}{2}(150 \cdot 10^{-6}F)(5 V)^2 = 1.88 \cdot 10^{-3}J$

6 0

4 years ago

Read 2 more answers

In 2005, the space probe Deep Impact launched a 370 kg projectile into Comet Temple 1. Observing the collision helped scientists

Ilya [14]

Parta a.

Equation: F = G*m1*m2/d^2

Where
F = 32 N
G = 6.67*10^-11 N.m^2/kg^2
m1 = 9.0*10^13kg
m2 =370 kg
d = distance that separate the center of the two objects.

d^2 = G*m1*m2 / F = 6.67*10^-11 N.m^2/kg^2 * 9.0*10^13 kg *370 kg / 32N = 69,409.69 m^2

d = √69,409.69m^2 = 263.5 m

Part B.

The gravitational field of the comet is g = G*m1/d^2

Notice that it does not depend on the mass of other objects.

Notice also that I will use a distance of 5.0 * 10^3 km, because I think that that is the number that you intended to write in the part b. If that is not the number you can put the right number instead because the solution is written step by step.

g = (6.67*10^-11 N*m^2/kg^2)*(9.0*10^13kg)/(5.0*10^3*10^3m)^2 = 2.4*10^-4 N/kg = 2.4*10^-4 m/s^2

3 0

4 years ago

What is a proper way and a safe way to dispose batteries

gregori [183]

Answer:

throw them away............

4 0

3 years ago

Read 2 more answers

A train is traveling north. it goes 200 km /hr for 2.5 hours how far did the train go.

DerKrebs [107]

Answer:

500Km

Explanation:

This question is an example of speed, distance, time.

The formula for working out the distance is: $Speed*Time$

To work this out you would need to multiply the speed of 200Km/h by the time of 2.5 hours, this gives you 500 Km. This is because the formula to work out the distance is speed * time.

In adittion, if the train is traveling at 200km per hour then that means that over the course of an hour the distance travelled would be 200Km. So, by multiplying the speed by the time you are working out how far it travelled in that given time.

1) Multiply 200 by 2.5.

$200*2.5=500Km$

5 0

3 years ago