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Arte-miy333 [17]
3 years ago
7

"Forensic entomologists study what to help solve crimes?"

Physics
2 answers:
Licemer1 [7]3 years ago
7 0
I believe the answer is flies since they study bugs, please get another opinion to be sure.

Inessa [10]3 years ago
7 0

Answer: Flies

Explanation:

Forensic entomology is the sub discipline of forensic science which use the insects and their life cycle to relate them with the decaying dead body. Insects found near the unknown dead body can be useful in establishing place of death, time since death, manner of death (poison or drug/alcohol toxicity).

On the basis of the above description, flies is the correct option because they are insects.

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Wave motion is characterized by two velocities: the velocity with which the wave moves in the medium (e.g., air or a string) and
Sindrei [870]

Answer: a) v = ω /k, b) v = - ωAcos( kx −ωt)

Explanation:

y(x,t)=Asin(kx−ωt) defines the wave equation.

a)

We are asked to find wave speed (v)

Recall that v = fλ

From the wave equation above,

k = 2π/ λ where k is the wave number and λ is the wavelength, λ = 2π /k

ω = 2πf where f is the frequency and ω is the angular frequency.

f = ω/ 2π.

By substituting for λ and ω into the wave speed formulae, we have that

v =( ω/ 2π) × (2π /k)

v = ω/k

b)

y(x,t)=Asin(kx−ωt)

The first derivative of y with respect to x give the velocity (vy)

By using chain rule, we have that

v = dy/dt = A cos( kx −ωt) × (−ω)

v = - ωAcos( kx −ωt)

3 0
3 years ago
The springs of a 1500 kg car compress 5.00 mm when its 68 kg driver gets into the driver's seat. Part A If the car goes over a b
elena-s [515]

Answer:

the frequency of the oscillation is 1.5 Hz

Explanation:

Given;

mass of the spring, m = 1500 kg

extention of the spring, x = 5 mm = 5 x 10⁻³ m

mass of the driver = 68 kg

The weight of the driver is calculated as;

F = mg

F = 68 x 9.8 = 666.4 N

The spring constant, k, is calculated as;

k = F/m

k = (666.4 N) / (5 x 10⁻³ m)

k = 133,280 N/m

The angular speed of the spring is calculated;

\omega = \sqrt{\frac{k}{m} } \\\\\omega = \sqrt{\frac{133280}{1500} } = 9.426 \ rad/s

The frequency of the oscillation is calculated as;

ω = 2πf

f = ω / 2π

f = (9.426) / (2π)

f = 1.5 Hz

Therefore, the frequency of the oscillation is 1.5 Hz

6 0
2 years ago
What are the largest and smallest resistances you can obtain by connecting a 36.0-Ω , a 50.0-Ω , and a 700-Ω resistor together?
myrzilka [38]
<h2>Answer:</h2>

786Ω and 20.32Ω respectively.

<h2>Explanation:</h2>

(a) Given a number of resistors each with its own resistance, the largest resistance can be obtained when these resistors are connected in series.

From the question, the resistors have the following resistances;

36.0-Ω, 50.0-Ω , and 700-Ω

Now, when they are connected in series, the total resistance (R) obtainable is given by the sum of these individual resistances as follows;

R = 36.0-Ω + 50.0-Ω + 700-Ω

R = 786Ω

Therefore, the largest resistance that can be obtained by connecting  a 36.0-Ω , a 50.0-Ω , and a 700-Ω resistor together is 786Ω

(b) Similarly, given a number of resistors each with its own resistance, the smallest resistance can be obtained when these resistors are connected in parallel.

From the question, the resistors have the following resistances;

36.0-Ω, 50.0-Ω , and 700-Ω

Now, when they are connected in parallel, the total resistance (R) obtainable is given by using the relation as follows;

\frac{1}{R} = \frac{1}{36.0} + \frac{1}{50.0} + \frac{1}{700.0}

\frac{1}{R} = \frac{35000+25200+1800}{1260000}

\frac{1}{R} = \frac{62000}{1260000}

\frac{1}{R} = \frac{62}{1260}

R = \frac{1260}{62}

R = 20.32Ω

Therefore, the smallest resistance that can be obtained by connecting  a 36.0-Ω , a 50.0-Ω , and a 700-Ω resistor together is 20.32Ω

7 0
3 years ago
What provides the vertical force to balance the force of gravity on the pendulum bob?
Zepler [3.9K]

Answer:

the string and metre rule

Explanation:

7 0
2 years ago
Elements that typically give up electrons
Naddika [18.5K]
Same answer as the first one above
8 0
3 years ago
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